不确定传参*numbers *list 关键字字典形式参数**kargs


def fun(name,age,**kwargs):
    return kwargs
print(fun('fqs','18',address="beijing",school='xy'))

'''
{'address': 'beijing', 'school': 'xy'}
'''

 




#
函数 不确定的参数情况下 输出 n*n的和 def calc(numbers): total=0 for n in numbers: print(f'n:{n}') total=total+n*n print(f'total:{total}') return total #调用函数 result=calc((1,2)) print(f'result:{result}') ''' this x is in the funcx:--> 9 -------------- this x is in the funcx:--> 9 '''
# 函数 不确定的参数情况下 输出 n*n的和
def calc(*numbers):
    total=0
    for n in numbers:
        print(f'n:{n}')
        total=total+n*n
        print(f'total:{total}')
    return total
#调用函数
result=calc(1,2,3)# 不需要强调以元祖形式传入参数
print(f'result:{result}')

 

# 函数 不确定的参数情况下 输出 n*n的和
def calc(*numbers):
    total=0
    for n in numbers:
        print(f'n:{n}')
        total=total+n*n
        print(f'total:{total}')
    return total
#调用函数
list=[1,2,3]
result=calc(*list)# 不需要强调以元祖形式传入参数 等同于result=calc(list[0],list[1],list[2])
 print(f'result:{result}') ''' n:1 total:1 n:2 total:5 n:3 total:14 result:14 '''

 

# 关键字可变参数  **kargs 多个字典key='value'参数
def register_student(name,age,**kargs):
    print('name:',name,'age:',age,'other:',kargs)
result1=register_student('fqs',35)
print(result1)
'''
name: fqs age: 35 other: {}
None
'''
# 传入一个字典key='value'参数
result2=register_student('d',3,address='beijing')
print(result2)
'''
name: d age: 3 other: {'address': 'beijing'}
'''
# 传入两个个字典key='value'参数
result3=register_student('d',3,city='beijing',school='chang')
print(result3)
'''
name: d age: 3 other: {'city': 'beijing', 'school': 'chang'}
'''

 

posted @ 2023-07-05 16:02  胖豆芽  阅读(9)  评论(0编辑  收藏  举报