在前一个文章序列化对象 :)中,我提到了
在这里,我使用了序列化,因为序列化的一个好处就是可以还原原始的HashCode,
即,序列化前的对象的GetHashCode()的返回值和序列化后还原的GetHashCode()的返回值是一样的:)
但是,我今天刚刚试了一下,发现不是这样的..示例代码如下:
注意:使用的时候加入前面的.NET中使用Mapping File 的API :)中提到了SharedMemory类
运行时分别运行两个,一个输入X,一个输入Y
这里,我把两个Client对象放到一个Hashtable中,再分别把这些个对象序列化,通过MappingFile传给另一个EXE程序.
再反序列化.结果,输出的是Fail,但是Hashtable中确实是有原始的Client对象..
结论:
通过这个例子,我发现,HashCode是和程序运行相关的,是相对于这个程序在当前运行期是唯一的.
所以了,我们如果想要把一个对象做为Hashtable中的Key同时把这个对象和这个Hashtable传给其它的应用程序(比如上面示例中的Client和Hashtalbe).请注意其对象的HashCode.:)
如果一定要传Hashtable过去.那么只要这个Hashtable的Key是.NET内置的数据类型,那照样可以正常使用:)
so,我前面文章中提到的那个结论(最上面有写)是错的.希望大家在使用中注意一下子.Have a good luck~
在这里,我使用了序列化,因为序列化的一个好处就是可以还原原始的HashCode,
即,序列化前的对象的GetHashCode()的返回值和序列化后还原的GetHashCode()的返回值是一样的:)
但是,我今天刚刚试了一下,发现不是这样的..示例代码如下:
using System;
using System.IO;
using System.Text;
using System.Collections;
using System.Runtime.Serialization.Formatters.Binary;
namespace TestForMapfile_Write
{
/// <summary>
/// Summary description for Class1.
/// </summary>
class Class1
{
/// <summary>
/// The main entry point for the application.
/// </summary>
[STAThread]
static void Main(string[] args)
{
Console.WriteLine("please input p / c or x / y: ");
SharedMemory sm = new SharedMemory();
SharedMemory smClient;
SharedMemory smHT;
Client client;
object obj;
switch( Console.ReadLine())
{
case "p":
case "P":
sm.Create( 10240,"Tiger");
client = new Client();
Console.WriteLine( client.GetHashCode());
client = new Client();
client.email = "tiger@msn.com";
client.id = 0;
client.name = "tiger";
sm.CopyFrom( Ser(client).ToArray());
Console.WriteLine( client.GetHashCode());
Console.WriteLine("ok");
Console.ReadLine();
break;
case "c":
case "C":
sm.Open( 10240,"Tiger");
MemoryStream ms = new MemoryStream( sm.CopyTo(0));
obj = Deser(ms);
Console.WriteLine( obj.GetHashCode());
Console.WriteLine("ok");
Console.ReadLine();
break;
case "x":
case "X":
smHT = new SharedMemory(10234,"smht");
smClient = new SharedMemory(10234,"smClient");
Hashtable ht = new Hashtable();
obj = new Client(1,"tiger","hh");
smClient.CopyFrom( Ser(obj).ToArray());
ht.Add( obj,1);
obj = new Client( 2,"unrule","unruldem");
smClient.CopyFrom( Ser(obj).ToArray());
ht.Add( obj,2);
smHT.CopyFrom( Ser(ht).ToArray());
Console.WriteLine("OK");
Console.ReadLine();
break;
case "y":
case "Y":
smHT = new SharedMemory();
smHT.Open(10234,"smht");
obj = Deser( new MemoryStream( smHT.CopyTo(0)));
smClient = new SharedMemory();
smClient.Open( 10234,"smClient");
object obj1 = Deser( new MemoryStream( smClient.CopyTo(0)));
if( ((Hashtable)obj).ContainsKey( (Client)obj1)){
Console.WriteLine("win");
}
else{
Console.WriteLine("Fail");
}
foreach( DictionaryEntry i in (Hashtable)obj){
Console.WriteLine( ((Client)i.Key).id);
}
Console.ReadLine();
break;
}
}
public static MemoryStream Ser(object obj){
MemoryStream ms = new MemoryStream();
BinaryFormatter formatter = new BinaryFormatter();
formatter.Serialize(ms,obj);
return ms;
}
public static object Deser(MemoryStream ms){
BinaryFormatter formatter = new BinaryFormatter();
return formatter.Deserialize(ms);
}
}
[Serializable]
class Client{
public int id;
public string name;
public string email;
public Client(){}
public Client(int ID,string Name,string Email){
id = ID;
name = Name;
email = Email;
}
}
}
using System.IO;
using System.Text;
using System.Collections;
using System.Runtime.Serialization.Formatters.Binary;
namespace TestForMapfile_Write
{
/// <summary>
/// Summary description for Class1.
/// </summary>
class Class1
{
/// <summary>
/// The main entry point for the application.
/// </summary>
[STAThread]
static void Main(string[] args)
{
Console.WriteLine("please input p / c or x / y: ");
SharedMemory sm = new SharedMemory();
SharedMemory smClient;
SharedMemory smHT;
Client client;
object obj;
switch( Console.ReadLine())
{
case "p":
case "P":
sm.Create( 10240,"Tiger");
client = new Client();
Console.WriteLine( client.GetHashCode());
client = new Client();
client.email = "tiger@msn.com";
client.id = 0;
client.name = "tiger";
sm.CopyFrom( Ser(client).ToArray());
Console.WriteLine( client.GetHashCode());
Console.WriteLine("ok");
Console.ReadLine();
break;
case "c":
case "C":
sm.Open( 10240,"Tiger");
MemoryStream ms = new MemoryStream( sm.CopyTo(0));
obj = Deser(ms);
Console.WriteLine( obj.GetHashCode());
Console.WriteLine("ok");
Console.ReadLine();
break;
case "x":
case "X":
smHT = new SharedMemory(10234,"smht");
smClient = new SharedMemory(10234,"smClient");
Hashtable ht = new Hashtable();
obj = new Client(1,"tiger","hh");
smClient.CopyFrom( Ser(obj).ToArray());
ht.Add( obj,1);
obj = new Client( 2,"unrule","unruldem");
smClient.CopyFrom( Ser(obj).ToArray());
ht.Add( obj,2);
smHT.CopyFrom( Ser(ht).ToArray());
Console.WriteLine("OK");
Console.ReadLine();
break;
case "y":
case "Y":
smHT = new SharedMemory();
smHT.Open(10234,"smht");
obj = Deser( new MemoryStream( smHT.CopyTo(0)));
smClient = new SharedMemory();
smClient.Open( 10234,"smClient");
object obj1 = Deser( new MemoryStream( smClient.CopyTo(0)));
if( ((Hashtable)obj).ContainsKey( (Client)obj1)){
Console.WriteLine("win");
}
else{
Console.WriteLine("Fail");
}
foreach( DictionaryEntry i in (Hashtable)obj){
Console.WriteLine( ((Client)i.Key).id);
}
Console.ReadLine();
break;
}
}
public static MemoryStream Ser(object obj){
MemoryStream ms = new MemoryStream();
BinaryFormatter formatter = new BinaryFormatter();
formatter.Serialize(ms,obj);
return ms;
}
public static object Deser(MemoryStream ms){
BinaryFormatter formatter = new BinaryFormatter();
return formatter.Deserialize(ms);
}
}
[Serializable]
class Client{
public int id;
public string name;
public string email;
public Client(){}
public Client(int ID,string Name,string Email){
id = ID;
name = Name;
email = Email;
}
}
}
注意:使用的时候加入前面的.NET中使用Mapping File 的API :)中提到了SharedMemory类
运行时分别运行两个,一个输入X,一个输入Y
这里,我把两个Client对象放到一个Hashtable中,再分别把这些个对象序列化,通过MappingFile传给另一个EXE程序.
再反序列化.结果,输出的是Fail,但是Hashtable中确实是有原始的Client对象..
结论:
通过这个例子,我发现,HashCode是和程序运行相关的,是相对于这个程序在当前运行期是唯一的.
所以了,我们如果想要把一个对象做为Hashtable中的Key同时把这个对象和这个Hashtable传给其它的应用程序(比如上面示例中的Client和Hashtalbe).请注意其对象的HashCode.:)
如果一定要传Hashtable过去.那么只要这个Hashtable的Key是.NET内置的数据类型,那照样可以正常使用:)
so,我前面文章中提到的那个结论(最上面有写)是错的.希望大家在使用中注意一下子.Have a good luck~