摘要: 题面戳我 \(\text{Solution:}\) \(\sum_{d=1}^nd^k\sum_{i=1}^\frac{n}{d}\sum_{j=1}^\frac{n}{d}[\gcd(i,j)=1]\) \(=\sum_{d=1}^n d^k\sum_{x=1}^\frac{n}{d}\mu(x) 阅读全文
posted @ 2020-08-12 20:22 Refined_heart 阅读(84) 评论(0) 推荐(0) 编辑