61. Rotate List

Given a linked list, rotate the list to the right by k places, where k is non-negative.

Example 1:

Input: 1->2->3->4->5->NULL, k = 2
Output: 4->5->1->2->3->NULL
Explanation:
rotate 1 steps to the right: 5->1->2->3->4->NULL
rotate 2 steps to the right: 4->5->1->2->3->NULL

Example 2:

Input: 0->1->2->NULL, k = 4
Output: 2->0->1->NULL
Explanation:
rotate 1 steps to the right: 2->0->1->NULL
rotate 2 steps to the right: 1->2->0->NULL
rotate 3 steps to the right: 0->1->2->NULL
rotate 4 steps to the right: 2->0->1->NULL
AC code:
/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode(int x) : val(x), next(NULL) {}
 * };
 */
class Solution {
public:
    ListNode* rotateRight(ListNode* head, int k) {
        if (!head) return NULL;
        ListNode* newN;
        ListNode* tail;
        newN = tail = head;
        int len = 1;
        while (tail->next) {
            tail = tail->next;
            len++;
        }
        tail->next = head;
        if (k %= len) {
            for (int i = 0; i < len - k; ++i) {
                tail = tail->next;
            }
        }
        newN = tail->next;
        tail->next = NULL;
        return newN;
    }
};

  

 

 

posted @ 2018-10-20 21:36  Veritas_des_Liberty  阅读(179)  评论(0编辑  收藏  举报