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Your task is to calculate the sum of some integers. 
Input
Input contains an integer N in the first line, and then N lines follow. Each line starts with a integer M, and then M integers follow in the same line. 
Output
For each group of input integers you should output their sum in one line, and you must note that there is a blank line between outputs. 
Sample Input
3
4 1 2 3 4
5 1 2 3 4 5
3 1 2 3
Sample Output
10

15

6



注意输出格式


我的代码



#include<stdio.h>
int main()
{
int i;
scanf("%d",&i);
for(int m=0;m<i;m++)
{
int a;
int p=0;
scanf("%d",&a);
for(int b=0;b<a;b++)
{
int q[100];
scanf("%d",&q[b]);
p+=q[b];
}
printf("%d\n",p);
}
return 0;
 } 
 


参考代码



#include<stdio.h>
int main()
{
 int test,t=0;
 scanf("%d",&test);
 while(test--)
 {
 int s=0,i;
 int n,a[1000];
 scanf("%d",&n);
 for(i=0;i<n;i++)
 {
 if(i==0)
 scanf("%d",&a[i]); // 这有的作用是的什么 
 else
 scanf(" %d",&a[i]);
 s+=a[i];
 }
 t++;
 if(t>1)
 printf("\n"); //输出格式  ps:机器就是笨 
 printf("%d\n",s);
 }
 return 0;
}
 




posted @ 2017-07-24 22:10  Veritas_des_Liberty  阅读(229)  评论(0编辑  收藏  举报