860. Lemonade Change
At a lemonade stand, each lemonade costs $5
.
Customers are standing in a queue to buy from you, and order one at a time (in the order specified by bills
).
Each customer will only buy one lemonade and pay with either a $5
, $10
, or $20
bill. You must provide the correct change to each customer, so that the net transaction is that the customer pays $5.
Note that you don't have any change in hand at first.
Return true
if and only if you can provide every customer with correct change.
Example 1:
Input: [5,5,5,10,20]
Output: true
Explanation:
From the first 3 customers, we collect three $5 bills in order.
From the fourth customer, we collect a $10 bill and give back a $5.
From the fifth customer, we give a $10 bill and a $5 bill.
Since all customers got correct change, we output true.
Example 2:
Input: [5,5,10]
Output: true
Example 3:
Input: [10,10]
Output: false
Example 4:
Input: [5,5,10,10,20]
Output: false
Explanation:
From the first two customers in order, we collect two $5 bills.
For the next two customers in order, we collect a $10 bill and give back a $5 bill.
For the last customer, we can't give change of $15 back because we only have two $10 bills.
Since not every customer received correct change, the answer is false.
Note:
0 <= bills.length <= 10000
bills[i]
will be either5
,10
, or20
.
Approach #1: C++.
class Solution { public: bool lemonadeChange(vector<int>& bills) { int billsOf5 = 0; int billsOf10 = 0; for (int i = 0; i < bills.size(); ++i) { if (bills[i] == 5) { billsOf5++; } else if (bills[i] == 10) { if (billsOf5 == 0) return false; billsOf5--; billsOf10++; } else { if (billsOf10 > 0 && billsOf5 > 0) { billsOf10--; billsOf5--; } else if (billsOf5 >= 3) { billsOf5 -= 3; } else return false; } } return true; } };
永远渴望,大智若愚(stay hungry, stay foolish)