#include<iostream>
using namespace std;
int main(void)
{
    int n;
    while(cin>>n)
        {
            if (n%4==2)
            cout<<"yes"<<endl;
            else 
            cout<<"no"<<endl;
        }
}

 

Problem Description
There are another kind of Fibonacci numbers: F(0) = 7, F(1) = 11, F(n) = F(n-1) + F(n-2) (n>=2).
 

 

Input
Input consists of a sequence of lines, each containing an integer n. (n < 1,000,000).
 

 

Output
Print the word "yes" if 3 divide evenly into F(n).

Print the word "no" if not.
 

 

Sample Input
0
1
2
3
4
5
 

 

Sample Output
no
no
yes
no
no
no
 
My Solution: