python sqlalchemy 动态设置表名__tablename__,一个model对应多个table

from sqlalchemy import create_engine,Column,BigInteger,String
from sqlalchemy.ext.declarative import declarative_base
from sqlalchemy.orm import sessionmaker
base = declarative_base()
engine = create_engine("postgresql://postgresadmin:admin123@192.168.214.133:32222/postgresdb")
class Test(base):
    __abstract__ = True #
    id = Column(BigInteger,primary_key=True)
    name = Column(String(255))
    tablename = Column(String(255))
    
    def __repr__(self) -> str:
        return self.tablename
    
session = sessionmaker(bind=engine)
Session = session()



# build a model class with a specific table name
def get_model(tablename,schema):
    Model = type(tablename, (Test,), {
        '__tablename__': tablename,
        '__table_args__':{"schema":schema}
    })
    return Model

model = get_model('test1','test')

value = Session.query(model).all()

for item in value:
    print(item)

  • 在抽象模型类中定义表列
  • 基于抽象模型构建一个模型类,并给它指定一个表名
  • 像使用常规类一样使用构建的模型类。
posted @ 2023-10-30 20:22  郭小睿  阅读(316)  评论(0编辑  收藏  举报