Android开发:Can't create handler inside thread that has not线程问题解决
一、问题如下
1、报错内容:Only the original thread that created a view hierarchy can touch its views.Only the original thread that created a view hierarchy can touch its views.
2、问题分析:在Android中不允许Activity里新启动的线程访问该Activity里的UI组件,Android中的UI是线程不安全的, 所有的更新UI操作都必须要在主线程中完成,而不能在新开的子线程中操作。
3、问题背景:
在从Android客户端向服务器发送数据,并在服务器端处理、返回数据接受之后,要显示在客户端的界面上。
由于网络相关的操作无法在主线程进行,只能通过新线程完成这个操作,而要显示在客户端的话,又必须要通过UI线程才能完成,因此就会报出上述错误。
这次就是在用Toast显示服务器端返回的数据时报的这个错。
二、问题解决
1、若想在异步线程前执行某些UI操作,比如更新progressBar进度条等操作,这种情况适合用runOnUiThread方法。
2、若想在线程中执行UI操作,还是要用Handler:
new Thread(new Runnable() { public void run() { try { URL url = new URL(strUrl); HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection(); //设置输入流采用字节流 urlConnection.setDoInput(true); //设置输出流采用字节流 urlConnection.setDoOutput(true); urlConnection.setRequestMethod("POST"); //设置缓存 urlConnection.setUseCaches(false); //设置meta参数 urlConnection.setRequestProperty("Content-Type", "application/x-www-form-urlencoded"); urlConnection.setRequestProperty("Charset", "utf-8"); //连接往服务器端发送消息 urlConnection.connect(); DataOutputStream dop = new DataOutputStream(urlConnection.getOutputStream()); dop.writeBytes("username=" + URLEncoder.encode(username, "utf-8") + "&password=" + URLEncoder.encode(password, "utf-8")); dop.flush(); dop.close(); BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(urlConnection.getInputStream())); String result = ""; String readLine = null; while ((readLine = bufferedReader.readLine()) != null) { result += readLine; } bufferedReader.close(); urlConnection.disconnect(); message=URLDecoder.decode(result, "utf-8").toString(); Handler handler = new Handler(Looper.getMainLooper()); handler.post(new Runnable() { @Override public void run() { Gson gson=new Gson(); Message m=gson.fromJson(message,Message.class); Toast.makeText(LoginActivity.this, m.getMessage(), Toast.LENGTH_LONG).show(); } }); } catch (Exception e) { e.printStackTrace(); } } }).start();