摘要: Code: 阅读全文
posted @ 2018-09-24 14:51 EM-LGH 阅读(130) 评论(0) 推荐(0) 编辑
摘要: Code:#include#include#includeusing namespace std;const int maxn = 200000 + 4;int lazy[maxn > 1; if(lazy[o]) { lazy[... 阅读全文
posted @ 2018-09-24 10:43 EM-LGH 阅读(135) 评论(0) 推荐(0) 编辑
摘要: Code:#include#include#includeusing namespace std;const int maxn = 2500 + 4;const int inf = 100000000;int f[maxn], sumv[maxn];int ... 阅读全文
posted @ 2018-09-24 10:39 EM-LGH 阅读(126) 评论(0) 推荐(0) 编辑