S-Nim POJ - 2960 Nim + SG函数

Code:

#include<cstdio>
#include<algorithm>
#include<string>
#include<cstring>
using namespace std;
#define maxn 10003
int step[maxn],SG[maxn],m,ans,l,a,k;
bool vis[maxn];
int main(){
    //freopen("input.in","r",stdin);
    while(scanf("%d",&k) && k){
       for(int i=1;i<=k;++i) scanf("%d",&step[i]);
       sort(step+1,step+1+k);
       SG[0]=0;
       for(int i=1;i<maxn;++i){
           for(int j=1;j<=k&&step[j]<=i;++j)vis[SG[i-step[j]]]=true;
           for(int j=0;;++j)if(!vis[j]) { SG[i]=j; break; }
           for(int j=1;j<=k&&step[j]<=i;++j)vis[SG[i-step[j]]]=false;
       }
       scanf("%d",&m);
       while(m--){
           scanf("%d",&l);
           ans=0;
           for(int i=1;i<=l;++i) scanf("%d",&a), ans^=SG[a];
           if(ans==0) printf("L");
           else printf("W");
       }
       printf("\n");
    }
    return 0;
}

 

posted @ 2018-11-06 16:20  EM-LGH  阅读(109)  评论(0编辑  收藏  举报