摘要: 1 select child.id,child.name,child.lft,child.rgt,count(child.name) depth2 from category parent, category child 3 where child.left >= parent.left 4 and 阅读全文
posted @ 2018-09-03 09:08 光何 阅读(2990) 评论(0) 推荐(0) 编辑