问题描述:
Given an array and a value, remove all instances of that value in-place and return the new length.
Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.
The order of elements can be changed. It doesn't matter what you leave beyond the new length.
代码如下: 3ms
int removeElement(int* nums, int numsSize, int val) { int length = 0; for(int i = 0;i<numsSize;++i) { if(nums[i] != val) { nums[length] = nums[i]; ++length; } } return length; }