第十二周--servlet做一个逻辑处理!!!!!!!!!!!!!实现登录

	public void doGet(HttpServletRequest request, HttpServletResponse response)
			throws ServletException, IOException {

       doPost(request,response);
	}

	
	public void doPost(HttpServletRequest request, HttpServletResponse response)
			throws ServletException, IOException {
		response.setContentType("text/html");
        response.setCharacterEncoding("utf-8");
	
		PrintWriter out = response.getWriter();
		out.println("<!DOCTYPE HTML PUBLIC \"-//W3C//DTD HTML 4.01 Transitional//EN\">");
		out.println("<HTML>");
		out.println("  <HEAD><TITLE>A Servlet</TITLE></HEAD>");
		out.println("  <BODY>");
		String username=request.getParameter("username");
		String password=request.getParameter("password");

		 if(username.equals("admin")&&password.equals("666")){
			 out.println("登陆成功");
		 }else{
			out.println("登陆失败");
		 }
		
		out.println("  </BODY>");
		out.println("</HTML>");
		out.flush();
		out.close();
	}

  

<body>
    <%request.setCharacterEncoding("utf-8"); %>
     <form action="FirstServlet" method="post" name="form1">
      账号:<input type="text" name="username" id="username">
      <br><br>
     密码: <input type="password" name="password" id="password">
      <br> <br>
     <input type="submit"  value="登录"  name="denglu"  onclick="yz()">
      </form>
        
  </body>

  

posted @ 2020-05-23 22:04  郭少锋18840631471  阅读(219)  评论(0编辑  收藏  举报