函数的超时

1、使用信号量实现函数的超时功能

from functools import wraps
import errno
import os
import signal
import time

class TimeoutError(Exception):
    pass

def timeout(seconds=10, error_message=os.strerror(errno.ETIME)):
    def decorator(func):
        def _handle_timeout(signum, frame):
            raise TimeoutError(error_message)

        def wrapper(*args, **kwargs):
            signal.signal(signal.SIGALRM, _handle_timeout)
            signal.alarm(seconds)
            try:
                result = func(*args, **kwargs)
            finally:
                signal.alarm(0)
            return result

        return wraps(func)(wrapper)

    return decorator

  

超时异常的修改:

class TimeoutError(Exception):
    def __init__(self, message=None, **kwargs):
        self.message = message
        super(TimeoutError, self).__init__(**kwargs)

    def __str__(self):
        return self.message

  

2、使用eventlet的Timeout

 

3、使用线程的Timer

 

http://stackoverflow.com/questions/2281850/timeout-function-if-it-takes-too-long-to-finish

posted @ 2015-03-03 17:29  小郭学路  阅读(336)  评论(0编辑  收藏  举报