将一维数组处理成树形结构数据

list是个一维数组数据,每项数据中有id和pid,id是自己的唯一标识符,pid是自己父级的id。

1 let list = [
2     {name:"1",id:"1"},
3     {name:"1-1",id:"1-1",pid:"1"},
4     {name:"1-1-1",id:"1-1-1",pid:"1-1"},
5     {name:"2",id:"2"},
6     {name:"2-1",id:"2-1",pid:"2"}
7 ]

 

 1 function dealOptions(list){
 2       let dealOptions = []
 3      // 给每个数据加children属性
 4      list.forEach( one => {
 5        one.children = []
 6       })
 7      list.forEach( one => {
 8        let findIndex = list.findIndex(item => {
 9           return item.id === one.pid
10        })
11       if ((!one.pid && one.pid !== 0 && one.pid !== false) || findIndex === -1) {
12          dealOptions.push(one)
13        } else {
14          list[findIndex].children.push(one)
15        }
16      })
17      return dealOptions
18  }

 

posted @ 2020-06-30 17:56  蛙仔  阅读(1188)  评论(0编辑  收藏  举报