【Android小技巧】判断设备是否root 参照bugly的实现方式

public static boolean p() {
        boolean var0 = false;
        String[] var1 = a;
        int var2 = a.length;

        for(int var3 = 0; var3 < var2; ++var3) {
            String var4 = var1[var3];
            if ((new File(var4)).exists()) {
                var0 = true;
                break;
            }
        }

        return Build.TAGS != null && Build.TAGS.contains("test-keys") || var0;
    }

private static final String[] a = new String[]{"/su", "/su/bin/su", "/sbin/su", "/data/local/xbin/su", "/data/local/bin/su", "/data/local/su", "/system/xbin/su", "/system/bin/su", "/system/sd/xbin/su", "/system/bin/failsafe/su", "/system/bin/cufsdosck", "/system/xbin/cufsdosck", "/system/bin/cufsmgr", "/system/xbin/cufsmgr", "/system/bin/cufaevdd", "/system/xbin/cufaevdd", "/system/bin/conbb", "/system/xbin/conbb"};

posted @ 2019-05-21 22:22  gregpeng  阅读(740)  评论(0编辑  收藏  举报