10 2014 档案

摘要:总有一部电影,让你憋着尿直到看完~~~http://share.renren.com/share/230538513/17679574169?from=0101090202&shfrom=010301002 阅读全文
posted @ 2014-10-31 12:40 Grandyang 阅读(572) 评论(0) 推荐(0) 编辑
摘要:ASCII控制字符二进制十进制十六进制缩写可以显示的表示法名称/意义00000000000NUL␀空字符(Null)00000001101SOH␁标题开始00000010202STX␂本文开始00000011303ETX␃本文结束00000100404EOT␄传输结束00000101505ENQ␅请... 阅读全文
posted @ 2014-10-30 07:52 Grandyang 阅读(1855) 评论(0) 推荐(0) 编辑
摘要:McGuire Computer Graphics Data http://mesh.brown.edu/calibration/software.html Pixar Online Library PLY Filesan ASCII Polygon Format 阅读全文
posted @ 2014-10-30 05:51 Grandyang 阅读(393) 评论(0) 推荐(0) 编辑
摘要:enum PixelFormatPixel formats available for Format7 modes.Enumerator: PIXEL_FORMAT_MONO88 bits of mono information.PIXEL_FORMAT_411YUV8YUV 4:1:1.PIXEL... 阅读全文
posted @ 2014-10-30 03:50 Grandyang 阅读(5682) 评论(0) 推荐(0) 编辑
摘要:You are given two integer arrays nums1 and nums2, sorted in non-decreasing order, and two integers m and n, representing the number of elements in num 阅读全文
posted @ 2014-10-29 15:25 Grandyang 阅读(21175) 评论(3) 推荐(1) 编辑
摘要:An enumeration of the different camera properties that can be set via the API.Declarationenum FlyCaptureProperty { FLYCAPTURE_BRIGHTNESS, FLYCAPTU... 阅读全文
posted @ 2014-10-27 13:24 Grandyang 阅读(1270) 评论(0) 推荐(0) 编辑
摘要:Given two binary trees, write a function to check if they are the same or not. Two binary trees are considered the same if they are structurally ident 阅读全文
posted @ 2014-10-27 07:54 Grandyang 阅读(14375) 评论(6) 推荐(0) 编辑
摘要:Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center). For example, this binary tree is symmetric: But the fol 阅读全文
posted @ 2014-10-26 10:49 Grandyang 阅读(17370) 评论(17) 推荐(2) 编辑
摘要:Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest l 阅读全文
posted @ 2014-10-26 07:32 Grandyang 阅读(22172) 评论(9) 推荐(0) 编辑
摘要:Given the root of a binary tree, return the bottom-up level order traversal of its nodes' values. (i.e., from left to right, level by level from leaf 阅读全文
posted @ 2014-10-26 05:23 Grandyang 阅读(13987) 评论(1) 推荐(0) 编辑
摘要:Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level). For example:Given binary tree {3 阅读全文
posted @ 2014-10-26 04:57 Grandyang 阅读(28828) 评论(11) 推荐(2) 编辑
摘要:How to read and write pixel dataBitmap processingImage StrideBayer Color Filter PatternHigh-Quality Algorithm for Bayer Pattern InterpolationToolBox:I... 阅读全文
posted @ 2014-10-24 10:54 Grandyang 阅读(532) 评论(0) 推荐(0) 编辑
摘要:8-Bit and 16-Bit Images关于量化压缩与量化补偿RGB Bayer Color分析彩色CCD/CMOS的格式和计算机中的读取格式 阅读全文
posted @ 2014-10-24 10:20 Grandyang 阅读(587) 评论(0) 推荐(0) 编辑
摘要:Point Grey areaDetector driverBumblebee XB3 Specifications FlyCapture SDK Example Source CodeUnderstanding Format_7 region of interest and pixel binni... 阅读全文
posted @ 2014-10-24 07:28 Grandyang 阅读(383) 评论(0) 推荐(0) 编辑
摘要:Integrating the FlyCapture SDK for use with OpenCVCStereoGrabber_Bumblebee.hOpenCV with PGR Flycapture camerashttp://www.cis.fordham.edu/twiki/pub/Mai... 阅读全文
posted @ 2014-10-24 07:16 Grandyang 阅读(371) 评论(1) 推荐(0) 编辑
摘要:Given a binary tree, determine if it is height-balanced. For this problem, a height-balanced binary tree is defined as: a binary tree in which the dep 阅读全文
posted @ 2014-10-23 13:59 Grandyang 阅读(18084) 评论(7) 推荐(0) 编辑
摘要:Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest l 阅读全文
posted @ 2014-10-22 07:27 Grandyang 阅读(18930) 评论(5) 推荐(3) 编辑
摘要:Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals the given sum. For example:Given the below binary tree and sum 阅读全文
posted @ 2014-10-22 06:45 Grandyang 阅读(18990) 评论(6) 推荐(1) 编辑
摘要:RT..将博客搬至CSDN 阅读全文
posted @ 2014-10-21 15:40 Grandyang 阅读(581) 评论(0) 推荐(0) 编辑
摘要:Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., [0,1,2,4,5,6,7] might become [4,5,6,7,0,1,2]). F 阅读全文
posted @ 2014-10-21 15:15 Grandyang 阅读(11245) 评论(4) 推荐(0) 编辑
摘要:ExampleLanguageDescriptionAsyncTriggerExC++Demonstrates some of the basic asynchronous trigger capabilities of compatible PGR Imaging Products.AsyncTr... 阅读全文
posted @ 2014-10-21 06:21 Grandyang 阅读(3660) 评论(1) 推荐(0) 编辑
摘要:Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum. N 阅读全文
posted @ 2014-10-20 13:08 Grandyang 阅读(17950) 评论(4) 推荐(0) 编辑
摘要:Suppose an array of length n sorted in ascending order is rotated between 1 and n times. For example, the array nums = [0,1,2,4,5,6,7] might become: [ 阅读全文
posted @ 2014-10-18 13:05 Grandyang 阅读(16815) 评论(14) 推荐(1) 编辑
摘要:Given a non-negative integer numRows, generate the first numRows of Pascal's triangle. In Pascal's triangle, each number is the sum of the two numbers 阅读全文
posted @ 2014-10-18 04:17 Grandyang 阅读(9911) 评论(2) 推荐(2) 编辑
摘要:Given a non-negative index k where k ≤ 33, return the kth index row of the Pascal's triangle. Note that the row index starts from 0. In Pascal's trian 阅读全文
posted @ 2014-10-17 16:52 Grandyang 阅读(12826) 评论(2) 推荐(0) 编辑
摘要:Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases. For example, "A man, a plan, a canal: Pa 阅读全文
posted @ 2014-10-17 04:09 Grandyang 阅读(21680) 评论(5) 推荐(3) 编辑
摘要:Given an integer array nums, find the contiguous subarray within an array (containing at least one number) which has the largest product. Example 1: E 阅读全文
posted @ 2014-10-16 14:24 Grandyang 阅读(27059) 评论(4) 推荐(2) 编辑
摘要:http://www.cnblogs.com/mfryf/archive/2012/03/31/2426324.html一 作用建立3D到2D的映射关系,一旦标定后,对于一个摄像机内部参数K(光心焦距变形参数等,简化的情况是只有f错切=0,变比=1,光心位置简单假设为图像中心),参数已知,那么根据2... 阅读全文
posted @ 2014-10-16 03:59 Grandyang 阅读(1330) 评论(0) 推荐(0) 编辑
摘要:Queuing:提交太多了,OJ无法在第一时间给所有提交以评判结果,后面提交的程序将暂时处于排队状态等待OJ的评判。不过这个过程一般不会很长。Compiling:您提交的代码正在被编译。Running:您的程序正在OJ上运行。Judging:OJ正在检查您程序的输出是否正确。Accepted(AC)... 阅读全文
posted @ 2014-10-15 07:57 Grandyang 阅读(1547) 评论(0) 推荐(0) 编辑
摘要:IdQuestionDifficultyFrequencyData StructuresAlgorithms1Two Sum25array + setsort + two pointers2Add Two Numbers34linked listtwo pointers + math3Longest... 阅读全文
posted @ 2014-10-15 05:40 Grandyang 阅读(4641) 评论(0) 推荐(1) 编辑
摘要:在以前介绍IplImage结构的时候,有一个重要的参数——ROI。ROI全称是”Region Of Interest”,即感兴趣的区域。实际上,它是IPL/IPP(这两个是Inter的库)结构IplROI的实例。IplROI包含xOffset、yOffset、height、width和coi成员变量... 阅读全文
posted @ 2014-10-10 06:20 Grandyang 阅读(3607) 评论(0) 推荐(0) 编辑
摘要:(OpenCV读取视频、OpenCV提取视频每一帧、每一帧图片合成新的AVI视频)CvCapture 是视频获取结构 被用来作为视频获取函数的一个参数 比如 CvCapture* cap; IplImage* cvQueryFrame( cap ); 从摄像头或者文件中抓取并返回一帧————————... 阅读全文
posted @ 2014-10-09 06:56 Grandyang 阅读(6655) 评论(1) 推荐(1) 编辑
摘要:今天推导公式,发现居然有对矩阵的求导,狂汗--完全不会。不过还好网上有人总结了。吼吼,赶紧搬过来收藏备份。基本公式:Y = A * X --> DY/DX = A'Y = X * A --> DY/DX = AY = A' * X * B --> DY/DX = A * B'Y = A' * X' ... 阅读全文
posted @ 2014-10-08 12:28 Grandyang 阅读(3638) 评论(0) 推荐(0) 编辑
摘要:指令功能应用实例LB从存储器中读取一个字节的数据到寄存器中LB R1, 0(R2)LH从存储器中读取半个字的数据到寄存器中LH R1, 0(R2)LW从存储器中读取一个字的数据到寄存器中LW R1, 0(R2)LD从存储器中读取双字的数据到寄存器中LD R1, 0(R2)L.S从存储器中读取单精度浮... 阅读全文
posted @ 2014-10-08 09:37 Grandyang 阅读(7863) 评论(0) 推荐(1) 编辑

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