【Android 逆向】【攻防世界】easyjni
1. apk 安装到手机,提示需要输入flag
2. jadx打开apk
public class MainActivity extends c {
static {
System.loadLibrary("native");
}
/* JADX INFO: Access modifiers changed from: private */
public boolean a(String str) {
try {
return ncheck(new a().a(str.getBytes()));
} catch (Exception e) {
return false;
}
}
private native boolean ncheck(String str);
/* JADX INFO: Access modifiers changed from: protected */
@Override // android.support.v7.app.c, android.support.v4.a.i, android.support.v4.a.aa, android.app.Activity
public void onCreate(Bundle bundle) {
super.onCreate(bundle);
setContentView(R.layout.activity_main);
findViewById(R.id.button).setOnClickListener(new View.OnClickListener() { // from class: com.a.easyjni.MainActivity.1
@Override // android.view.View.OnClickListener
public void onClick(View view) {
if (MainActivity.this.a(((EditText) ((MainActivity) this).findViewById(R.id.edit)).getText().toString())) {
Toast.makeText(this, "You are right!", 1).show();
} else {
Toast.makeText(this, "You are wrong! Bye~", 1).show();
}
}
});
}
}
/* loaded from: classes.dex */
public class a {
private static final char[] a = {'i', '5', 'j', 'L', 'W', '7', 'S', '0', 'G', 'X', '6', 'u', 'f', '1', 'c', 'v', '3', 'n', 'y', '4', 'q', '8', 'e', 's', '2', 'Q', '+', 'b', 'd', 'k', 'Y', 'g', 'K', 'O', 'I', 'T', '/', 't', 'A', 'x', 'U', 'r', 'F', 'l', 'V', 'P', 'z', 'h', 'm', 'o', 'w', '9', 'B', 'H', 'C', 'M', 'D', 'p', 'E', 'a', 'J', 'R', 'Z', 'N'};
public String a(byte[] bArr) {
StringBuilder sb = new StringBuilder();
for (int i = 0; i <= bArr.length - 1; i += 3) {
byte[] bArr2 = new byte[4];
byte b = 0;
for (int i2 = 0; i2 <= 2; i2++) {
if (i + i2 <= bArr.length - 1) {
bArr2[i2] = (byte) (b | ((bArr[i + i2] & 255) >>> ((i2 * 2) + 2)));
b = (byte) ((((bArr[i + i2] & 255) << (((2 - i2) * 2) + 2)) & 255) >>> 2);
} else {
bArr2[i2] = b;
b = 64;
}
}
bArr2[3] = b;
for (int i3 = 0; i3 <= 3; i3++) {
if (bArr2[i3] <= 63) {
sb.append(a[bArr2[i3]]);
} else {
sb.append('=');
}
}
}
return sb.toString();
}
}
这个a类感觉就是自定义字典的base64算法
3. IDA打开so看看
bool __fastcall Java_com_a_easyjni_MainActivity_ncheck(JNIEnv *nev, jobject a2, jstring key)
{
const char *key_chars; // r6
int i; // r0
char *v7; // r2
char v8; // r1
int v9; // r0
bool v10; // cc
char v12[32]; // [sp+3h] [bp-35h] BYREF
char v13; // [sp+23h] [bp-15h]
key_chars = (*nev)->GetStringUTFChars(nev, key, 0);
if ( strlen(key_chars) == 32 )
{
for ( i = 0; i != 16; ++i )
{
v7 = &v12[i];
v12[i] = key_chars[i + 16];
v8 = key_chars[i];
v7[16] = v8;
}
(*nev)->ReleaseStringUTFChars(nev, key, key_chars);
v9 = 0;
do
{
v10 = v9 < 30;
v13 = v12[v9];
v12[v9] = v12[v9 + 1];
v12[v9 + 1] = v13;
v9 += 2;
}
while ( v10 );
return memcmp(v12, "MbT3sQgX039i3g==AQOoMQFPskB1Bsc7", 0x20u) == 0;
}
else
{
(*nev)->ReleaseStringUTFChars(nev, key, key_chars);
return 0;
}
}
整理以下算法
for ( i = 0; i != 16; ++i )
{
//v7 = &v12[i];
v12[i] = key_chars[i + 16];
tmp = key_chars[i];
v12[i+16] = tmp;
}
(*nev)->ReleaseStringUTFChars(nev, key, key_chars);
i = 0;
do
{
v10 = i < 30;
tmp = v12[i];
v12[i] = v12[i + 1];
v12[i + 1] = tmp;
i += 2;
}
while ( v10 );
return memcmp(v12, "MbT3sQgX039i3g==AQOoMQFPskB1Bsc7", 0x20u) == 0;
也和之前的一样,先前16位和后16位交换,然后两两交换,借助之前写的python还原算法
key = 'MbT3sQgX039i3g==AQOoMQFPskB1Bsc7'
def main():
print(key)
key_list = list(key)
t_len = len(key)
i = 0
v19 = 0
while v19 < t_len:
tmp = key_list[i+2]
key_list[i+2] = key_list[i+3]
key_list[i+3] = tmp
v19 = i+4
i += 2
tmp = key_list[1]
key_list[1] = key_list[0]
key_list[0] = tmp
print("after ======")
print(''.join(key_list))
i = 0
while i < t_len >> 1:
tmp = key_list[i+16]
key_list[i+16] = key_list[i]
key_list[i] = tmp
i += 1
print("after ======")
print(''.join(key_list))
main()
# 得到
QAoOQMPFks1BsB7cbM3TQsXg30i9g3==