手写tomcat——编写一个echo http服务器

核心代码如下:

public class DiyTomcat1 {

    public void run() throws IOException {
        ServerSocket serverSocket = new ServerSocket(8080);
        System.out.println("======服务启动成功========");
        while (!serverSocket.isClosed()) {
            Socket socket = serverSocket.accept();
            InputStream inputStream = socket.getInputStream();
            System.out.println("执行客户请求:" + Thread.currentThread());
            System.out.println("收到客户请求");
            BufferedReader reader = new BufferedReader(new InputStreamReader(inputStream, "utf-8"));
            String msg = null;
            while ((msg = reader.readLine()) != null) {
                if (msg.length() == 0) {
                    break;
                }
                System.out.println(msg);
            }
            String rspHeaderStr = "HTTP/1.1 200" + "\r\n" + "Content-Type:text/html" + "\r\n\r\n";
            String resp = rspHeaderStr + "OK";
            OutputStream outputStream = socket.getOutputStream();
            System.out.println("=====rsp====");
            System.out.println(resp);
            outputStream.write(resp.getBytes());
            outputStream.flush();
            outputStream.close();
            socket.close();
        }
    }
}


这是一个最基本的socket通信流程:

  1. 首先通过创建一个ServerSocket实例, 该实例拥有监听端口的能力
  2. 通过调用serverSocket的accept方法来监听并接受连接
  3. 当有客户端连接上来会返回一个socket对象,该对象代表着这次通信的连接
  4. 通过socket.getInputStream来获得客户端向服务端的输入(流)
  5. 通过socket.getOutputStream来获得服务端向客户端的输出流,并通过调用write方法将我们要发送的数据写入
  6. String rspHeaderStr = "HTTP/1.1 200" + "\r\n" + "Content-Type:text/html" + "\r\n\r\n"; 是为了构造出一个http 协议的头部,方便客户端解析(如果是浏览器http请求过来,可以方便浏览器直接展示处理)

代码地址:
https://github.com/ZhongJinHacker/diy-tomcat/tree/base-tomcat

posted @ 2021-10-03 11:08  明月照江江  阅读(71)  评论(0编辑  收藏  举报