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循环链表解决约瑟夫环问题

 1 /**
 2  * 循环链表求解约瑟夫环问题
 3  **/
 4 #include <iostream>
 5 #include <cstdlib>
 6 using namespace std;
 7 
 8 /**
 9  * 数据结构
10  **/
11 typedef struct DanamicList {
12     int id;
13     struct DanamicList* next;
14 } List;
15 
16 /**
17  * 创建循环链表
18  **/
19 List* InitList(int numCount) {
20     if(numCount <= 0) {
21         cout << "Value is invalid!!!\n";
22         exit(-1);
23     }
24     List *head = head = new List;
25     if(!head) {
26         cout << "Alloc memory failed!!!\n";
27         exit(-1);
28     }
29 
30     head->id = 1;
31     List *pre = head;
32     for(int index = 1; index < numCount; ++index) {
33         List *temp = new List;
34         if(!temp) {
35             cout << "Alloc memory failed!!!\n";
36             exit(-1);
37         }
38         temp->id = index + 1;
39         temp->next = NULL;
40         pre->next = temp;
41         pre = temp;
42     }
43     pre->next = head;
44 
45     return head;
46 }
47 
48 /**
49  * 求解约瑟夫环问题
50  **/
51 void josephus(List* head, int number) {
52     int count = 0, flag = 0;
53     List *pre = head, *del = NULL;
54 
55     while(pre->next != head)
56         pre = pre->next;
57     do {
58         ++count;
59         if(number != count)
60             pre = pre->next;
61         else {
62             count = 0;
63             del = pre->next;
64             cout << del->id << "\t";
65             pre->next = pre->next->next;
66             if (pre != pre->next)
67                 delete del;
68         }
69         if(pre == pre->next)
70             ++flag;
71     } while(flag - (number + 1));             // 数学关系
72     delete pre;
73 }
74 
75 /**
76  * 主函数
77  **/
78 int main(void) {
79     List *head = NULL;
80     int totalPeople = 0, outNumber = 0;
81     cout << "请输入总数和出队密码:";
82     cin >> totalPeople;
83     cin >> outNumber;
84 
85     head = InitList(totalPeople);             // 创建循环链表
86     josephus(head, outNumber);                // 求解约瑟夫环
87 
88     return 0;
89 }

 

posted @ 2014-07-14 21:55  dai.sp  阅读(347)  评论(0编辑  收藏  举报