【转载】破解SQL Server加密的存储过程的方法(含 sql 2000与sql 2005版)
转载自:http://www.cnblogs.com/zhou__zhou/archive/2010/04/17/sqlserver.html
http://www.cnblogs.com/huqingyu/archive/2007/12/17/997296.html
SQLServer2005里使用with encryption选项创建的存储过程仍然和sqlserver2000里一样,都是使用XOR进行了的加密。和2000不一样的是,在2005的系统表syscomments里已经查不到加密过的密文了。要查密文必须使用DAC(专用管理员连接)连接到数据库后,在系统表sys.sysobjvalues查询,该表的列imageval存储了相应的密文。具体可以使用下面的查询:
SELECT imageval FROM sys.sysobjvalues WHERE objid = object_id(@procedure) AND
valclass = 1 AND subobjid = 1
案例2:有接手别人工作,而对于业务存储过程中使用加密了内容的,维护难受啊,GOOGLE搜索,终于不负有心人.Sql2000的。
CREATE PROCEDURE usp_decrypt(@objectname varchar(50))
AS
begin
set nocount on
--CSDN:j9988 copyright:2004.07.15
--V3.2
--破解字节不受限制,适用于SQLSERVER2000存储过程,函数,视图,触发器
--修正上一版"视图触发器"不能正确解密错误
--发现有错,请E_MAIL:CSDNj9988@tom.com
begin tran
declare @objectname1 varchar(100),@orgvarbin varbinary(8000)
declare @sql1 nvarchar(4000),@sql2 varchar(8000),@sql3 nvarchar(4000),@sql4 nvarchar(4000)
DECLARE @OrigSpText1 nvarchar(4000), @OrigSpText2 nvarchar(4000) , @OrigSpText3 nvarchar(4000), @resultsp nvarchar(4000)
declare @i int,@status int,@type varchar(10),@parentid int
declare @colid int,@n int,@q int,@j int,@k int,@encrypted int,@number int
select @type=xtype,@parentid=parent_obj from sysobjects where id=object_id(@objectname)
create table #temp(number int,colid int,ctext varbinary(8000),encrypted int,status int)
insert #temp SELECT number,colid,ctext,encrypted,status FROM syscomments WHERE id = object_id(@objectname)
select @number=max(number) from #temp
set @k=0
while @k<=@number
begin
if exists(select 1 from syscomments where id=object_id(@objectname) and number=@k)
begin
if @type='P'
set @sql1=(case when @number>1 then 'ALTER PROCEDURE '+ @objectname +';'+rtrim(@k)+' WITH ENCRYPTION AS '
else 'ALTER PROCEDURE '+ @objectname+' WITH ENCRYPTION AS '
end)
if @type='TR'
begin
declare @parent_obj varchar(255),@tr_parent_xtype varchar(10)
select @parent_obj=parent_obj from sysobjects where id=object_id(@objectname)
select @tr_parent_xtype=xtype from sysobjects where id=@parent_obj
if @tr_parent_xtype='V'
begin
set @sql1='ALTER TRIGGER '+@objectname+' ON '+OBJECT_NAME(@parentid)+' WITH ENCRYPTION INSTERD OF INSERT AS PRINT 1 '
end
else
begin
set @sql1='ALTER TRIGGER '+@objectname+' ON '+OBJECT_NAME(@parentid)+' WITH ENCRYPTION FOR INSERT AS PRINT 1 '
end
end
if @type='FN' or @type='TF' or @type='IF'
set @sql1=(case @type when 'TF' then
'ALTER FUNCTION '+ @objectname+'(@a char(1)) returns @b table(a varchar(10)) with encryption as begin insert @b select @a return end '
when 'FN' then
'ALTER FUNCTION '+ @objectname+'(@a char(1)) returns char(1) with encryption as begin return @a end'
when 'IF' then
'ALTER FUNCTION '+ @objectname+'(@a char(1)) returns table with encryption as return select @a as a'
end)
if @type='V'
set @sql1='ALTER VIEW '+@objectname+' WITH ENCRYPTION AS SELECT 1 as f'
set @q=len(@sql1)
set @sql1=@sql1+REPLICATE('-',4000-@q)
select @sql2=REPLICATE('-',8000)
set @sql3='exec(@sql1'
select @colid=max(colid) from #temp where number=@k
set @n=1
while @n<=CEILING(1.0*(@colid-1)/2) and len(@sql3)<=3996
begin
set @sql3=@sql3+'+@'
set @n=@n+1
end
set @sql3=@sql3+')'
exec sp_executesql @sql3,N'@sql1 nvarchar(4000),@ varchar(8000)',@sql1=@sql1,@=@sql2
end
set @k=@k+1
end
set @k=0
while @k<=@number
begin
if exists(select 1 from syscomments where id=object_id(@objectname) and number=@k)
begin
select @colid=max(colid) from #temp where number=@k
set @n=1
while @n<=@colid
begin
select @OrigSpText1=ctext,@encrypted=encrypted,@status=status FROM #temp WHERE colid=@n and number=@k
SET @OrigSpText3=(SELECT ctext FROM syscomments WHERE id=object_id(@objectname) and colid=@n and number=@k)
if @n=1
begin
if @type='P'
SET @OrigSpText2=(case when @number>1 then 'CREATE PROCEDURE '+ @objectname +';'+rtrim(@k)+' WITH ENCRYPTION AS '
else 'CREATE PROCEDURE '+ @objectname +' WITH ENCRYPTION AS '
end)
if @type='FN' or @type='TF' or @type='IF'
SET @OrigSpText2=(case @type when 'TF' then
'CREATE FUNCTION '+ @objectname+'(@a char(1)) returns @b table(a varchar(10)) with encryption as begin insert @b select @a return end '
when 'FN' then
'CREATE FUNCTION '+ @objectname+'(@a char(1)) returns char(1) with encryption as begin return @a end'
when 'IF' then
'CREATE FUNCTION '+ @objectname+'(@a char(1)) returns table with encryption as return select @a as a'
end)
if @type='TR'
begin
if @tr_parent_xtype='V'
begin
set @OrigSpText2='CREATE TRIGGER '+@objectname+' ON '+OBJECT_NAME(@parentid)+' WITH ENCRYPTION INSTEAD OF INSERT AS PRINT 1 '
end
else
begin
set @OrigSpText2='CREATE TRIGGER '+@objectname+' ON '+OBJECT_NAME(@parentid)+' WITH ENCRYPTION FOR INSERT AS PRINT 1 '
end
end
if @type='V'
set @OrigSpText2='CREATE VIEW '+@objectname+' WITH ENCRYPTION AS SELECT 1 as f'
set @q=4000-len(@OrigSpText2)
set @OrigSpText2=@OrigSpText2+REPLICATE('-',@q)
end
else
begin
SET @OrigSpText2=REPLICATE('-', 4000)
end
SET @i=1
SET @resultsp = replicate(N'A', (datalength(@OrigSpText1) / 2))
WHILE @i<=datalength(@OrigSpText1)/2
BEGIN
SET @resultsp = stuff(@resultsp, @i, 1, NCHAR(UNICODE(substring(@OrigSpText1, @i, 1)) ^
(UNICODE(substring(@OrigSpText2, @i, 1)) ^
UNICODE(substring(@OrigSpText3, @i, 1)))))
SET @i=@i+1
END
set @orgvarbin=cast(@OrigSpText1 as varbinary(8000))
set @resultsp=(case when @encrypted=1
then @resultsp
else convert(nvarchar(4000),case when @status&2=2 then uncompress(@orgvarbin) else @orgvarbin end)
end)
print @resultsp
set @n=@n+1
end
end
set @k=@k+1
end
drop table #temp
rollback tran
end
再有一个Sql 2005 版的
SQLServer2005里使用with encryption选项创建的存储过程仍然和sqlserver2000里一样,都是使用XOR进行了的加密。和2000不一样的是,在2005的系统表syscomments里已经查不到加密过的密文了。要查密文必须使用DAC(专用管理员连接)连接到数据库后,在系统表sys.sysobjvalues查询,该表的列imageval存储了相应的密文。具体可以使用下面的查询:
SELECT imageval FROM sys.sysobjvalues WHERE objid = object_id(@procedure) AND
valclass = 1 AND subobjid = 1
DAC连接,在数据库引擎查询时,服务器名称前添加admin:
例:服务器名pc001则应使用 admin:pc001
create PROCEDURE [dbo].[usp_decrypt]
(@procedure sysname = NULL, @revfl int = 1)
AS
/**//*
王成辉翻译整理,转贴请注明出自微软BI开拓者www.windbi.com
目前这个存储过程只能解密存储过程,至于解密函数、触发器、视图的存储过程本网站会进一步关注,调用形式为:
exec dbo.usp_decrypt procedure,0
如果第二个参数使用1的话,会给出该存储过程的一些提示。
--版本3.0 修正存储过程过长引起的问题
*/
SET NOCOUNT ON
IF @revfl = 1
BEGIN
PRINT '警告:该存储过程会删除并重建原始的存储过程。'
PRINT ' 在运行该存储过程之前确保你的数据库有一个备份。'
PRINT ' 该存储过程通常应该运行在产品环境的一个备份的非产品环境下。'
PRINT ' 为了运行这个存储过程,将参数@refl的值更改为0。'
RETURN 0
END
DECLARE @intProcSpace bigint, @t bigint, @maxColID smallint,@procNameLength int
select @maxColID = max(subobjid) FROM
sys.sysobjvalues WHERE objid = object_id(@procedure)
--select @maxColID as 'Rows in sys.sysobjvalues'
select @procNameLength = datalength(@procedure) + 29
DECLARE @real_01 nvarchar(max)
DECLARE @fake_01 nvarchar(max)
DECLARE @fake_encrypt_01 nvarchar(max)
DECLARE @real_decrypt_01 nvarchar(max),@real_decrypt_01a nvarchar(max)
declare @objtype varchar(2),@ParentName nvarchar(max)
select @real_decrypt_01a = ''
--提取对象的类型如是存储过程还是函数,如果是触发器,还要得到其父对象的名称
select @objtype=type,@parentname=object_name(parent_object_id)
from sys.objects where [object_id]=object_id(@procedure)
-- 从sys.sysobjvalues里提出加密的imageval记录
SET @real_01=(SELECT top 1 imageval FROM sys.sysobjvalues WHERE objid =
object_id(@procedure) and valclass = 1 order by subobjid)
--创建一个临时表
create table #output ( [ident] [int] IDENTITY (1, 1) NOT NULL ,
[real_decrypt] NVARCHAR(MAX) )
--开始一个事务,稍后回滚
BEGIN TRAN
--更改原始的存储过程,用短横线替换
if @objtype='P'
SET @fake_01='ALTER PROCEDURE '+ @procedure +' WITH ENCRYPTION AS
'+REPLICATE(cast('-'as nvarchar(max)), datalength(@real_01) /2 - @procNameLength)
else if @objtype='FN'
SET @fake_01='ALTER FUNCTION '+ @procedure +'() RETURNS INT WITH ENCRYPTION AS BEGIN RETURN 1
/*'+REPLICATE(cast('*'as nvarchar(max)), datalength(@real_01) /2 - @procNameLength)+'*/ END'
else if @objtype='V'
SET @fake_01='ALTER view '+ @procedure +' WITH ENCRYPTION AS select 1 as col
/*'+REPLICATE(cast('*'as nvarchar(max)), datalength(@real_01) /2 - @procNameLength)+'*/'
else if @objtype='TR'
SET @fake_01='ALTER trigger '+ @procedure +' ON '+@parentname+'WITH ENCRYPTION AFTER INSERT AS RAISERROR (''N'',16,10)
/*'+REPLICATE(cast('*'as nvarchar(max)), datalength(@real_01) /2 - @procNameLength)+'*/'
EXECUTE (@fake_01)
--从sys.sysobjvalues里提出加密的假的
SET @fake_encrypt_01=(SELECT top 1 imageval FROM sys.sysobjvalues WHERE objid =
object_id(@procedure) and valclass = 1 order by subobjid )
if @objtype='P'
SET @fake_01='Create PROCEDURE '+ @procedure +' WITH ENCRYPTION AS
'+REPLICATE(cast('-'as nvarchar(max)), datalength(@real_01) /2 - @procNameLength)
else if @objtype='FN'
SET @fake_01='CREATE FUNCTION '+ @procedure +'() RETURNS INT WITH ENCRYPTION AS BEGIN RETURN 1
/*'+REPLICATE(cast('*'as nvarchar(max)), datalength(@real_01) /2 - @procNameLength)+'*/ END'
else if @objtype='V'
SET @fake_01='Create view '+ @procedure +' WITH ENCRYPTION AS select 1 as col
/*'+REPLICATE(cast('*'as nvarchar(max)), datalength(@real_01) /2 - @procNameLength)+'*/'
else if @objtype='TR'
SET @fake_01='Create trigger '+ @procedure +' ON '+@parentname+'WITH ENCRYPTION AFTER INSERT AS RAISERROR (''N'',16,10)
/*'+REPLICATE(cast('*'as nvarchar(max)), datalength(@real_01) /2 - @procNameLength)+'*/'
--开始计数
SET @intProcSpace=1
--使用字符填充临时变量
SET @real_decrypt_01 = replicate(cast('A'as nvarchar(max)), (datalength(@real_01) /2 ))
--循环设置每一个变量,创建真正的变量
--每次一个字节
SET @intProcSpace=1
--如有必要,遍历每个@real_xx变量并解密
WHILE @intProcSpace<=(datalength(@real_01)/2)
BEGIN
--真的和假的和加密的假的进行异或处理
SET @real_decrypt_01 = stuff(@real_decrypt_01, @intProcSpace, 1,
NCHAR(UNICODE(substring(@real_01, @intProcSpace, 1)) ^
(UNICODE(substring(@fake_01, @intProcSpace, 1)) ^
UNICODE(substring(@fake_encrypt_01, @intProcSpace, 1)))))
SET @intProcSpace=@intProcSpace+1
END
--通过sp_helptext逻辑向表#output里插入变量
insert #output (real_decrypt) select @real_decrypt_01
-- select real_decrypt AS '#output chek' from #output --测试
-- -------------------------------------
--开始从sp_helptext提取
-- -------------------------------------
declare @dbname sysname
,@BlankSpaceAdded int
,@BasePos int
,@CurrentPos int
,@TextLength int
,@LineId int
,@AddOnLen int
,@LFCR int --回车换行的长度
,@DefinedLength int
,@SyscomText nvarchar(max)
,@Line nvarchar(255)
Select @DefinedLength = 255
SELECT @BlankSpaceAdded = 0 --跟踪行结束的空格。注意Len函数忽略了多余的空格
CREATE TABLE #CommentText
(LineId int
,Text nvarchar(255) collate database_default)
--使用#output代替sys.sysobjvalues
DECLARE ms_crs_syscom CURSOR LOCAL
FOR SELECT real_decrypt from #output
ORDER BY ident
FOR READ ONLY
--获取文本
SELECT @LFCR = 2
SELECT @LineId = 1
OPEN ms_crs_syscom
FETCH NEXT FROM ms_crs_syscom into @SyscomText
WHILE @@fetch_status >= 0
BEGIN
SELECT @BasePos = 1
SELECT @CurrentPos = 1
SELECT @TextLength = LEN(@SyscomText)
WHILE @CurrentPos != 0
BEGIN
--通过回车查找行的结束
SELECT @CurrentPos = CHARINDEX(char(13)+char(10), @SyscomText,
@BasePos)
--如果找到回车
IF @CurrentPos != 0
BEGIN
--如果@Lines的长度的新值比设置的大就插入@Lines目前的内容并继续
While (isnull(LEN(@Line),0) + @BlankSpaceAdded +
@CurrentPos-@BasePos + @LFCR) > @DefinedLength
BEGIN
SELECT @AddOnLen = @DefinedLength-(isnull(LEN(@Line),0) +
@BlankSpaceAdded)
INSERT #CommentText VALUES
( @LineId,
isnull(@Line, N'') + isnull(SUBSTRING(@SyscomText,
@BasePos, @AddOnLen), N''))
SELECT @Line = NULL, @LineId = @LineId + 1,
@BasePos = @BasePos + @AddOnLen, @BlankSpaceAdded = 0
END
SELECT @Line = isnull(@Line, N'') +
isnull(SUBSTRING(@SyscomText, @BasePos, @CurrentPos-@BasePos + @LFCR), N'')
SELECT @BasePos = @CurrentPos+2
INSERT #CommentText VALUES( @LineId, @Line )
SELECT @LineId = @LineId + 1
SELECT @Line = NULL
END
ELSE
--如果回车没找到
BEGIN
IF @BasePos <= @TextLength
BEGIN
--如果@Lines长度的新值大于定义的长度
While (isnull(LEN(@Line),0) + @BlankSpaceAdded +
@TextLength-@BasePos+1 ) > @DefinedLength
BEGIN
SELECT @AddOnLen = @DefinedLength -
(isnull(LEN(@Line),0) + @BlankSpaceAdded)
INSERT #CommentText VALUES
( @LineId,
isnull(@Line, N'') + isnull(SUBSTRING(@SyscomText,
@BasePos, @AddOnLen), N''))
SELECT @Line = NULL, @LineId = @LineId + 1,
@BasePos = @BasePos + @AddOnLen, @BlankSpaceAdded =
0
END
SELECT @Line = isnull(@Line, N'') +
isnull(SUBSTRING(@SyscomText, @BasePos, @TextLength-@BasePos+1 ), N'')
if LEN(@Line) < @DefinedLength and charindex(' ',
@SyscomText, @TextLength+1 ) > 0
BEGIN
SELECT @Line = @Line + ' ', @BlankSpaceAdded = 1
END
END
END
END
FETCH NEXT FROM ms_crs_syscom into @SyscomText
END
IF @Line is NOT NULL
INSERT #CommentText VALUES( @LineId, @Line )
select Text from #CommentText order by LineId
CLOSE ms_crs_syscom
DEALLOCATE ms_crs_syscom
DROP TABLE #CommentText
-- -------------------------------------
--结束从sp_helptext提取
-- -------------------------------------
--删除用短横线创建的存储过程并重建原始的存储过程
ROLLBACK TRAN
DROP TABLE #output
已经打包好的文件下载在这里 https://files.cnblogs.com/zhou__zhou/T-SQL%e7%a0%b4%e8%a7%a3%e5%8a%a0%e5%af%86%e7%9a%84%e5%ad%98%e5%82%a8%e8%bf%87%e7%a8%8b.rar
引用网摘:
http://www.windbi.com/showtopic-153.aspx
http://www.easte.cn/post/SQL_Server_SP_Decrypt_ALL.html
解密SQL2005存储过程要使用DAC模式连接到SQL2005数据库处理
转载自:
http://hi.baidu.com/lzj1981/blog/item/ed436a62f5eb25d7e6113a0f.html
http://www.taotechinfo.com/collect/2010322/n13188930.html
如果你在网上找到破解SQL2005加密的存储过程,运行时提示不成功,那么你可要使用DAC模式连接到SQL2005数据库来处理,方法如下:
1、打开 SQL Server Management Studio
2、登录框 按“取消”
3、工具栏上的第一个图标:数据库引擎查询
4、服务器名称前加“ADMIN:”,如:ADMIN:hostname\sql2005
5、选择“Windows 身份验证”,或输入sa和密码,登录。
已打开 SQL Server Management Studio 并连接,忽略1、2步。
如果出现:provider: SQL 网络接口, error: 43 - 在获取专用的管理员连接(DAC)端口时出错。 确保正在运行 SQL 浏览器,或检查错误日志中是否有该端口号的错误
原因可能是:
The firewall on the server has refused the connection.
A specified SQL Server instance name is not valid.
The SQL Server Browser service (sqlbrowser) is not started.(打开Sql Server里的 SQL Server Brower 数据库浏览服务)
需要执行:
sp_configure 'remote admin connections', 1
GO
RECONFIGURE
这样一般都可以连接成功的
SQL Server2005中如何知道某个存储过程是否已加密?
转载自:http://www.cnblogs.com/gis_gps/archive/2009/01/16/1377133.html
最近在写一个小软件,需要知道当前那些存储过程已经被加密,如果被加密,则调用解密过程,将其解密,还原明文保存。基于sql server2005解密已加密的存储过程,网上有成熟的代码可供参考,但如何通过sql 语句的方式知道当前数据库中的存储过程是否已加密呢??
最初我就认为加密与不加密的存储过程肯定是一个标记位,存放在某个系统表中,但这个系统表在那里?我却不知道,曾通过google或msdn去查找,但没有找到相关资料,甚至准备写邮件咨询邹建等大侠....
突然想到,原来经常利用sp_helptext查看某个未加密过程的明文,那如果用sp_helptext查看已加密的过程,会有什么反映呢。结果很明确,系统提示:对象***文件已加密!
呵呵,既然sp_helptext知道这个过程已经加密,那我查看一下sp_helptext源码不就可以知道,它是如何判断出该过程是否已加密的吗?
于是,输入:exec sp_helptext sp_helptext ,屏幕上果然输出sp_helptext的明文,从sp_helptext中我们很容易找到这行code:
select text from syscomments where id = @objid and encrypted = 0............
这段代码意思很明确,查询输出未加密的过程,那么我所需要的就是:
select * from syscomments where encrypted = 1
好了,说到这里,我想各位已经很清楚知道如何解决本文开头所提出的问题!祝各位好运!
===================================================================
示例
加密:
create procedure p_test
with encryption
as
select * from test
解密:
use [test]
exec sp_decrypt 'p_test'