Object与RTTI

1.定义

结合前面的内容，可以定义如下的基类

 1 class Object : public Memory
 2 {
 3     DECL_TPLT(Object);
 4     DECL_RTTI(Object);
 5 public:
 6     bool        isKindOf(me::Type type) const
 7     {
 8         return getType().isKindOf(type);
 9     }
10     bool        isExactKindOf(me::Type type) const
11     {
12         return getType().isExactKindOf(type);
13     }
14     const char*    getTypeName()const
15     {
16         return getType().getName();
17     }
18 };

定义继承类型

class DerivedObject : public me::Object
{
    DECL_TPLT(DerivedObject);
    DECL_RTTI(DerivedObject, Object);
};
template <typename T>
class TemplateObject : public DerivedObject
{
    DECL_TPLT(TemplateObject, T);
    DECL_RTTI(TemplateObject, DerivedObject);
};

2.使用

 1     DerivedObject* pdo1 = new DerivedObject();
 2     Object* po1 = pdo1->getType().newObject();
 3     if (pdo1->getType() == pdo1->getType()) {
 4         std::cout << "po1 is an instance of " << po1->getType().getName() << std::endl;
 5         DerivedObject* pdo2 = static_cast<DerivedObject*>(po1);
 6     }
 7     typedef TemplateObject<Object*> TObject;
 8     Type tobj = TObject::TypeId;
 9     std::cout << tobj.getName() << ":" << tobj.getHash() << std::endl;
10     Type btdobj = tobj.getBaseTypes()[0];
11     std::cout << btdobj.getName() << ":" << btdobj.getHash() << std::endl;
12     Type tbase = Object::TypeId;
13     if (tobj.isKindOf(tbase)) {
14         std::cout << tobj.getName() << " is kind of " << tbase.getName();
15     }
16     delete pdo1;

3.结果

posted @ 2016-07-06 22:59  goooon  阅读(174)  评论(0)  编辑  收藏  举报