LeetCode-0310
121.买卖股票的最佳时机
python
# 记录下最低交易价格,同时记录目前为止最高收益
def MaxProfit(prices):
maxprofit,minprice = 0,prices[0]
for price in prices:
maxprofit = max(price-minprice,maxprofit)
minprice = min(price,minprice)
return maxprofit
c++
class Solution {
public:
int maxProfit(vector<int>& prices) {
if(!prices.empty()){
int maxprofit = 0;
int minprices = prices[0];
for(auto price:prices){
maxprofit = max(price-minprices,maxprofit);
minprices = min(price,minprices);
}
return maxprofit;
}
else{
return 0;
}
}
};
543.二叉树的直径
python
#深度优先遍历,递归求节点深度, 找到最大深度,减一即为长度
class Solution:
def diameterOfBinaryTree(self, root: TreeNode) -> int:
self.ans = 0
def depth(node):
if not node:
return 0
left = depth(node.left)#递归左儿子深度
right = depth(node.right)
self.ans = max(left+right+1,self.ans)#保存最大深度
return max(left,right)+1
depth(root)
return self.ans-1
c++
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
int ans; //声明全局变量
int depth(TreeNode* node){
if(node == NULL){
return 0;
}
int L = depth(node->left);
int R = depth(node->right);
ans = max(L+R+1,ans);
return max(L,R)+1;
}
public:
int diameterOfBinaryTree(TreeNode* root) {
if(root==NULL){
return 0;
}
ans = 0;
depth(root);
return ans-1;
}
};
255.用队列实现栈
python
class MyStack:
def __init__(self):
"""
Initialize your data structure here.
"""
self.stack = []
def push(self, x: int) -> None:
"""
Push element x onto stack.
"""
self.stack.append(x)
def pop(self) -> int:
"""
Removes the element on top of the stack and returns that element.
"""
return self.stack.pop(-1)
def top(self) -> int:
"""
Get the top element.
"""
return self.stack[-1]
def empty(self) -> bool:
"""
Returns whether the stack is empty.
"""
if self.stack:
return False
else:
return True
c++
# 单队列实现
class MyStack {
public:
/** Initialize your data structure here. */
MyStack() {
}
/** Push element x onto stack. */
void push(int x) {
que.push(x);
for(int i=0;i+1<que.size();i++){ //push 后队列size已经改变
int temp = que.front();
que.pop();
que.push(temp);
}
}
/** Removes the element on top of the stack and returns that element. */
int pop() {
int val = top();
que.pop();
return val;
}
/** Get the top element. */
int top() {
return que.front();
}
/** Returns whether the stack is empty. */
bool empty() {
return que.empty();
}
private:
queue<int> que;
};