关于Java中fastjson处理json的整理(补充)

1,字符串转JSON对象

String result = "{'XXX',[{'XXX','XXX'},{'XXX','XXX'}]}";
JSONObject jsonObject = JSON.parseObject(result);

2,字符串转JSON对象(解决排序问题)

String textObject = "{'XXX',[{'XXX','XXX'},{'XXX','XXX'}]}";
 JSONObject json2 = JSONObject.parseObject(textObject, Feature.OrderedField);

3,字符串转JSON数组对象

JSONArray jsonArray = JSONArray.parseArray(map.get("resultList").toString());

4,字符串转JSON数组对象(解决排序问题,取出时不打乱顺序)

JSONArray jsonArr = (JSONArray) JSONObject.parse(ss, Feature.OrderedField);

5,遍历JSON对象

String textObject = "{"obj1":{"userNmae":"lisi"},"obj2":{"userNmae":"lisi2"},"obj3":{"userNmae":"lisi3"}}";
int i = 1;
JSONObject json2 = JSONObject.parseObject(textObject, Feature.OrderedField);
Iterator<String> iterator2 = json2.keySet().iterator();
while (iterator2.hasNext()) {
     String key = iterator2.next();
     System.out.println(i + " : " + json2.get(key));
     i++;
}

6,遍历JSON数组

JSONArray  whiteBoardBookList = JSONArray.parseArray(whiteBoardBook);
Iterator<Object> iterator = whiteBoardBookList.iterator();
while (iterator.hasNext()) {
	JSONObject object = (JSONObject) iterator.next();
	stringBuilder.append(object.get("id"));
	if(iterator.hasNext()) {
		stringBuilder.append(",");
	}
}

7,JSON对象存数据顺序不变的方法

JSONObject courseware = new JSONObject(true)

注:JSON不用转list或map或ObJect,可以直接使用JSONArray,JSONObject,JSONObject来代替处理数据。

posted @ 2021-08-17 17:40  把兰舟弃了  阅读(215)  评论(0编辑  收藏  举报