【模拟】爱与愁的一千个伤心的理由

原题传送门

思路

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这道题的题目我是真的无力吐槽，但是，这道题真心不错QAQ。

这道题不难，但很考验耐心与细心，有各种各样的小错误，如果不细心都不会发现，我最开始的代码只得了60分，就是忽略了好几个情况，然后反复测试数据，才AC的QAQ（也许只是因为我太弱了）

值得一刷

Code

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#include<iostream>
#include<cstdio>
#include<string>
#include<vector>
#include<algorithm>
#include<cstdlib>
#include<cmath>
#include<stack>
#include<map>
using namespace std;

int n;
int s[5];
string a[25]={"","one","two","three",
"four","five","six","seven","eight","nine",
"ten","eleven","twelve","thirteen","fourteen",
"fifteen","sixteen","seventeen","eighteen","nineteen"};
string x[20]={"","","twenty","thirty","forty","fifty",
"sixty","seventy","eighty","ninety"};
int main()
{
	cin>>n;
	int i=4;
	while(n!=0)
	{
		s[i]=n%10;
		n/=10;
		i--;
	}
    if(s[1]!=0)
    	cout<<a[s[1]]<<" thousand ";
	if(s[2]!=0)
    	cout<<a[s[2]]<<" hundred ";	
	else if(s[3]!=0&&s[4]!=0&&(s[2]!=0||s[1]!=0))
		cout<<"and ";		
	if(s[3]==0&&s[4]!=0&&(s[2]!=0||s[1]!=0))
    	cout<<"and "<<a[s[4]]<<endl;
    else if(s[3]==0&&s[4]!=0)
		cout<<a[s[4]]<<endl;
    else if(s[3]==1)
    	cout<<a[s[4]+10]<<endl;
    else if(s[4]!=0)
    	cout<<x[s[3]]<<" "<<a[s[4]];
    if(s[1]==0&&s[2]==0&&s[3]==0&&s[4]==0)
		cout<<"zero";
    return 0;
}