lintcode-medium-Anagrams

Given an array of strings, return all groups of strings that are anagrams.

Given ["lint", "intl", "inlt", "code"], return["lint", "inlt", "intl"].

Given ["ab", "ba", "cd", "dc", "e"], return["ab", "ba", "cd", "dc"].

public class Solution {
    /**
     * @param strs: A list of strings
     * @return: A list of strings
     */
    public List<String> anagrams(String[] strs) {
        // write your code here
        
        List<String> result = new ArrayList<String>();
        
        if(strs == null || strs.length == 0)
            return result;
        
        HashMap<String, ArrayList<String>> map = new HashMap<String, ArrayList<String>>();
        
        for(int i = 0; i < strs.length; i++){
            String temp = getCount(strs[i]);
            
            if(!map.containsKey(temp))
                map.put(temp, new ArrayList<String>());
            
            map.get(temp).add(strs[i]);
        }
        
        for(ArrayList<String> value: map.values()){
            if(value.size() > 1)
                result.addAll(value);
        }
        return result;
    }
    
    public String getCount(String str){
        StringBuilder result = new StringBuilder();
        int[] count = new int[26];
        
        for(int i = 0; i < str.length(); i++){
            count[str.charAt(i) - 'a']++;
        }
        
        for(int i = 0; i < 26; i++)
            result.append(count[i]);
        
        return result.toString();
    }
    
}