摘要：
可以用String.join 方法 String.join("/", stack);每个元素之间用"/"分开 阅读全文
摘要：
1 class Solution { 2 public String addBinary(String a, String b) { 3 if(a.length() == 0 && b.length() == 0) return null; 4 StringBuilder sb1 = new StringBuilder(a); 5 ... 阅读全文
摘要：
1 class Solution { 2 public int minPathSum(int[][] grid) { 3 if(grid == null) return 0; 4 int row = grid.length; 5 int col = grid[0].length; 6 int[][] res = ... 阅读全文
摘要：
1 class Solution { 2 public int uniquePathsWithObstacles(int[][] obstacleGrid) { 3 if(obstacleGrid == null) return 0; 4 int row = obstacleGrid.length; 5 int col = obs... 阅读全文