#include<iostream> 
using namespace std;
int main(){
    int year,mouth,day,x=0,i;
    int a[12]={31,28,31,30,31,30,31,31,30,31,30,31};
    scanf("%d%d%d",&year,&mouth,&day);
    if(year-1990<=2)
    x=(year-1990)*365+day;
    else
    x=365*2+((year-1-1992)/4+1)*366+(year-1992-((year-1-1992)/4+1))*365+day;
    if((year%4==0&&year%100!=0)||(year%400==0))
    a[1]=29;
    for(i=0;i<mouth-1;i++)
    x=x+a[i]; 
    if(x%5<=3&&x%5>0)
    printf("今天打鱼");
    else
    printf("今天晒网");
    printf("%d",x);
    return 0; 
}

首先先分为1992年之前和1992年之后两种情况,因为1992是第一个闰年从这里分开方便计算