mysql json 字段获取值

PG 

get_json_object(remark, '$.字段英文名')

-- MYSQL  

aa=[{"tableName":"CBONDDESCRIPTION","alias":"a","tableId":476}]

JSON_UNQUOTE(JSON_EXTRACT(aa,'$[0].tableName')) as ddd,

ps:JSON_UNQUOTE  去除双引号

   中文记得双引号哦 JSON_UNQUOTE(JSON_EXTRACT(resps, '$."合并资产负债表"')) AS table_name_value