代码改变世界

字典方法

2017-10-08 23:48  单曲的轨迹  阅读(192)  评论(0编辑  收藏  举报
# users = {"name":"niuhy","age":18}
# #取值
# # print(users['lanxia']) #如果key不存在的话,会报错
# # print(users.get('lanxia')) #如果key不存在的话,会返回None
#
# #改
# users["name"]='dasx'
# users.update(name='haha')
# #增
# users['addr']='回龙观'
# users.setdefault('sex','男')
# #删
# # del users['name']
# # users.pop('sex')
# # users.popitem()#随机删
# #字典是无须
#
# # print(users.items())
# # for k,v in users.items(): #同时循环k和value
# # print("%s=%s"%(k,v))
# # for k in users:
# # print("%s=%s"%(k,users[k]))
#
# #用in来判断一个值是不是字典里面的话,判断是字典key
#
# #niuhanyang,123456
# # users = {
# # "zyl":"123456",
# # "jmt":"789123",
# # "wjx":"niuhanyang"
# # }
# # if 'niuhanyang' in users:
# # print('ok')
# # else:
# # print('bu ok')
# user_info={
# "jmy":{
# "money":100,
# "shengao":1.5,
# "password":"123456"
# },
# "agr":{
# "money":250,
# "shengao":"lishuiqiao",
# "password":"123456"
# }
# }
# f=open('users.txt','a+',encoding='utf-8')
# f.seek(0)
# # list()
# # int()
# # float()
# # str()
# # tuple()
# # dict()
# new_user_info= eval(f.read())#把字符串转成字典
# print(type(new_user_info))