摘要: 1 long long Quick_Pow (long long m, long long n, long long mo) 2 { 3 long long ret = 1; 4 while (n) 5 { 6 if (n & 1) ret = (ret * m) % mo; 7 n >>= 1; m = (m * m... 阅读全文
posted @ 2016-10-22 10:34 -搁浅- 阅读(104) 评论(0) 推荐(0) 编辑