摘要：
---兩個時間之差的合計DECLARE @I INTSET @I = DATEDIFF(ms,GETDATE()-RAND()*24,GETDATE())SELECT convert(varchar(10), @I/86400000) + ' Days ' + convert(varchar(10), (@I%86400000)/3600000) + ' Hours '+ convert(varchar(10), (@I%3600000)/60000) + ' Mins '+ convert(varchar(10), (@I%60000)/100 阅读全文
