python: 压缩图片.webp

pip install imageio

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1 2	image = imageio.imread("1.jpg") imageio.imwrite("output_image.webp", image, "WEBP")

　　

 

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# 代码示例：使用Python的Keras库构建Autoencoder模型 from keras.models import Model from keras.layers import Input, Dense   input_img = Input(shape=(784,)) encoded = Dense(128, activation='relu')(input_img) decoded = Dense(784, activation='sigmoid')(encoded)   autoencoder = Model(input_img, decoded) autoencoder.compile(optimizer='adam', loss='binary_crossentropy')

 

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rows, cols = (10, 10) # 创建一个真正的二维数组 F = [[0 for _ in range(cols)] for _ in range(rows)] n = int(input('请输入数字:')) y = 0   while y < rows:     x = 0     while x < cols:         for i in range(y, y + n):             for j in range(x, x + n):                 if(i<=9 and j<=9):                     F[i][j] = 1         x += n * 2  # 用于每个隔一个相同的距离x 的坐标     y += n * 2  # 用于每个隔一个相同的距离y的坐标 #打印效果 for row in F:     for col in row:         print(col, end=" ")     print()

　　

 

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rows, cols = (10, 10)  # 创建一个真正的二维数组  F = [[0 for _ in range(cols)] for _ in range(rows)]  n = int(input('请输入数字:'))  y = 0    while y < rows:      x = 0      while x < cols:          for i in range(y, min(y + n, rows)):              for j in range(x, min(x + n, cols)):                  F[i][j] = 1          x += n * 2  # 用于每个隔一个相同的距离x 的坐标      y += n * 2  # 用于每个隔一个相同的距离y的坐标  #打印效果  for row in F:      for col in row:          print(col, end=" ")      print()      letter_array = [      "JGJGDDAOYD",      "IDGFHSPOSA",      "FGDIOSAFSC",      "INTERNETSO",      "FJKCOSAFSM",      "DJSGAPAHDP",      "HAUSTRFBFU",      "KDGFUCNSKT",      "WSJDYCFXDE",      "ODVFKXJVCR"  ]    word = input("请输入单词: ")  word = word.upper()  find = False    if not letter_array or not word:      print("输入的单词为空或字符串数组为空。")  else:      rows = len(letter_array)      word_length = len(word)        # 遍历所有行      for row in letter_array:          # 在每一行中，从左到右滑动单词长度的窗口          for start_col in range(len(row) - word_length + 1):              # 检查当前窗口的字符串是否与单词匹配              if row[start_col:start_col + word_length] == word:                  find = True  # 如果在某一行的窗口中找到单词，则返回True                  break  # 找到单词后立即退出循环          if find:              break  # 找到单词后立即退出循环        if find:          print(f"单词 '{word}' 存在于字符串数组的行线上。")      else:          print(f"单词 '{word}' 不存在于字符串数组的任何行线上。")          letter_array = [      "JGJGDDAOYD",      "IDGFHSPOSA",      "FGDIOSAFSC",      "INTERNETSO",      "FJKCOSAFSM",      "DJSGAPAHDP",      "HAUSTRFBFU",      "KDGFUCNSKT",      "WSJDYCFXDE",      "ODVFKXJVCR"  ]    word = input("请输入单词: ")  word = word.upper()  rows = len(letter_array)  cols = len(letter_array[0]) if rows > 0 else 0  word_length = len(word)  find = False    # 检查所有可能的起始位置  for i in range(rows):      for j in range(cols):          # 检查当前位置是否在数组的边界内，如果这个单词可以放在对角线上          if i + word_length <= rows and j + word_length <= cols:              # 检查单词是否与对角线匹配              match = True              for k in range(word_length):                  if letter_array[i + k][j + k] != word[k]:                      match = False                      break              if match:                  find = True                  break  # 找到匹配后立即停止搜索      if find:          break  # 找到匹配后立即停止搜索    if find:      print(f"单词 '{word}' 存在于字符串数组的对角线上。")  else:      print(f"单词 '{word}' 不存在于字符串数组的任何对角线上。")      letter_array = [      "JGJGDDAOYD",      "IDGFHSPOSA",      "FGDIOSAFSC",      "INTERNETSO",      "FJKCOSAFSM",      "DJSGAPAHDP9",      "HAUSTRFBFU",      "KDGFUCNSKT",      "WSJDYCFXDE",      "ODVFKXJVCR"  ]    word = "CAR"  word = input("please enter word:")  word = word.upper()  rows = len(letter_array)  cols = len(letter_array[0]) if rows > 0 else 0  find=False  # 所有可能的index起始位置  for i in range(rows):      for j in range(cols):          # 检查当前位置是否在数组的边界内          # ，如果这个单词可以放在index上          if i + len(word) <= rows and j + len(word) <= cols:              # 检查单词是否与index匹配              match = True              for k in range(len(word)):                  if letter_array[i + k][j + k] != word[k]:                      match = False                      break              if match:                  find= True  if find:      print(f"The word '{word}' exists in the letter array as a diagonal.")  else:      print(f"The word '{word}' does not exist in the letter array as a diagonal.")      letter_array = [      "JGJGDDAOYD",      "IDGFHSPOSA",      "FGDIOSAFSC",      "INTERNETSO",      "FJKCOSAFSM",      "DJSGAPAHDP",      "HAUSTRFBFU",      "KDGFUCNSKT",      "WSJDYCFXDE",      "ODVFKXJVCR"  ]          word = "MPUTER"  # 在一列部分的位置  word=input("输入要在列中查找的单词")  # 转换为大写以便与letter_array中的字符进行比较  word = word.upper()  find=False  if not letter_array or not word:      find= False    cols = len(letter_array[0])  rows = len(letter_array)  word_length = len(word)    # 遍历所有列  for j in range(cols):      # 在每一列中，从顶部到底部滑动单词长度的窗口      for start_row in range(rows - word_length + 1):          # 检查当前窗口的字符串是否与单词匹配          match = True          for i in range(word_length):              if letter_array[start_row + i][j] != word[i]:                  match = False                  break          if match:              find= True  # 如果在某一列的窗口中找到单词，则返回True    if find:      print(f"The word Part '{word}' exists in the letter array as a column.")  else:      print(f"The word Part '{word}' does not exist in the letter array as a column.")

　　

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rows, cols = (10, 10)  F = [[0 for _ in range(cols)] for _ in range(rows)]  n = int(input("please number:"))  y = 0  while y < rows:      x = 0      while x < cols:          for i in range(y, y + n ):              for j in range(x, x + n):                  if i <= 9 and j <= 9:                      F[i][j] = 1          x += n * 2      y += n * 2    # 打印效果  for row in F:      for col in row:          print(col, end=" ")      print()      rows, cols = (10, 10)  # 创建一个真正的二维数组  F = [[0 for _ in range(cols)] for _ in range(rows)]  n = int(input('请输入数字:'))  y = 0    while y < rows:      x = 0      while x < cols:          for i in range(y, min(y + n,rows)):              for j in range(x, min(x + n,cols)):                  F[i][j] = 1          x += n * 2  # 用于每个隔一个相同的距离x 的坐标      y += n * 2  # 用于每个隔一个相同的距离y的坐标  #打印效果  for row in F:      for col in row:          print(col, end=" ")      print()