HDU4631Sad Love Story

这道题是用multiset直接维护就行了（可是我根本不会multiset)

用一些剪枝就能跑出来

还有

不要爆int

#include <set>
#include <cstdio>
#include <cstring>
#include <iostream>
#include <algorithm>
using namespace std;
const long long inf=1ll<<60;
inline int read(){
	int x=0,f=1,ch=getchar();
	while(ch<'0'||ch>'9'){if(ch=='-')f=-1;ch=getchar();}
	while(ch>='0'&&ch<='9'){x=x*10+ch-'0';ch=getchar();}
	return x*f;
}
struct point{
	long long x,y;
	bool operator < (const point &b)const{
		return x<b.x;
	}
};
multiset<point> s;
int main(){
	int T=read();
	while(T--){
		 int n=read(),Ax=read(),Bx=read(),Cx=read(),Ay=read(),By=read(),Cy=read();
		 s.clear();point a=(point){0,0};
		 long long ans=0,minn=inf;
		 for(int i=1;i<=n;i++){
		 	a.x=(a.x*Ax+Bx)%Cx;
		 	a.y=(a.y*Ay+By)%Cy;
		 	// cout<<a.x<<"\t"<<a.y<<endl;
		 	if(i!=1){
			 	multiset<point>::iterator p=s.lower_bound(a),it;
			 	for(it=p;it!=s.end();it++){
			 		long long dx=a.x-it->x;
			 		dx*=dx;
			 		if(dx>=minn) break;
			 		long long dy=a.y-it->y;
			 		dy*=dy;
			 		minn=min(minn,dx+dy);
			 	}
			 	for(it=p;it!=s.begin();){
			 		it--;
			 		long long dx=a.x-it->x;
			 		dx*=dx;
			 		if(dx>=minn) break;
			 		long long dy=a.y-it->y;
			 		dy*=dy;
			 		minn=min(minn,dx+dy);
			 	}
			 	ans+=minn;
			 	// cout<<minn<<endl;
		 	}
		 	s.insert(a);
		 }
		 printf("%lld\n",ans);
	}
	return 0;
}