575. 进制转化
题目描述
给定一个十进制正整数,要求输出这个正整数的二进制数、八进制数和十六进制数。
解答要求时间限制:1000ms, 内存限制:100MB
输入
输入数据只有一行,包含一个十进制正整数x(1 <= x <= 1000000000)
输出
输出一共3行,第一行输出二进制数,第二行输出八进制数,第三行输出十六进制数,十六进制数中的字母采用大写字母。
样例
输入样例 1 复制
13
输出样例 1
1101 15 D
提示样例 1
代码:
// we have defined the necessary header files here for this problem. // If additional header files are needed in your program, please import here. void Trans_two(int N) { int a[1005],i = 0; while(N>0) { int t = N%2; N = N/2; a[i] = t; i++; } for (int k = i-1;k>=0;k--) cout<<a[k]; cout<<endl; } void Trans_eight(int N) { int a[1005],i = 0; while(N>0) { int t = N%8; N = N/8; a[i] = t; i++; } for (int k = i-1;k>=0;k--) cout<<a[k]; cout<<endl; } void Trans_sixteen(int N) { char arr []= "0123456789ABCDEF"; char hex[16]; int i = 0; while(N>0) { hex[i++] = arr[N%16]; N = N/16; } for (int k = i-1;k>=0;--k) cout<<hex[k]; cout<<endl; } int main() { // please define the C++ input here. For example: int a,b; cin>>a>>b;; // please finish the function body here. // please define the C++ output here. For example:cout<<____<<endl; int N; cin>>N; Trans_two(N); Trans_eight(N); Trans_sixteen(N); return 0; }
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