Leetcode[154]-Find Minimum in Rotated Sorted Array II

Link：　https://leetcode.com/problems/find-minimum-in-rotated-sorted-array-ii/

Follow up for "Find Minimum in Rotated Sorted Array":
What if duplicates are allowed?

Would this affect the run-time complexity? How and why?

Suppose a sorted array is rotated at some pivot unknown to you beforehand.

(i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2).

Find the minimum element.

The array may contain duplicates.

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方法一：直接遍历求解

class Solution {
public:
    int findMin(vector<int>& nums) {

        int n = nums.size();
        int min = nums[0];
        for(int  i = 1; i < n; i++) {
            if(nums[i]<min){
                min = nums[i];
            }
        }
        return min;
    }
};