ANSYS-APDL施加扭转载荷CERIG命令
1. 要求
一块0.8m*0.4m*0.04m厚的钢板,在板的两侧有一个弯矩的作用,弯矩大小为500N*m,试用有限元的方法计算板的应力分布状态。
2. ANSYS有限元分析
2.1 APDL建模
!程序头
FINISH
/CLEAR
/FILENAME, VSR
/PREP7
!设置单元
ET,1,SOLID185
ET,2,MASS21
R,2,1E-6,1E-6,1E-6,0,0,0,
!设置材料-钢
MP,EX,1,210E9
MP,NUXY,1,0.33
MP,DENS,1,7850
!建立模型
BLC4,0,0,0.8,0.4,0.04
!创建点
K,9,-0.1,0.2,0.02
K,10,0.9,0.2,0.02
!设置属性
TYPE,1
MAT,1
!设置网格划分
LESIZE,1,,,20
LESIZE,2,,,40
LESIZE,9,,,10
VMESH,ALL
!点划分网格
TYPE,2
REAL,2
KSEL,S,,,9,10,,
KMESH,ALL
ALLSEL
EPLOT
2.2 APDL施加载荷
!施加固定约束,选取中间的几个节点
NSEL,S,LOC,X,0.4,0.4
NSEL,R,LOC,Z,0.02,0.03
NPLOT
D,ALL,ALL
ALLSEL
!左侧耦合
NSEL,S,LOC,X,-0.1,0
NPLOT
!CERIG,NODE(-0.1,0.2,0.02),ALL,ALL,,,,
CERIG,9472,ALL,ALL,,,,
ALLSEL
!右侧耦合
NSEL,S,LOC,X,0.8,0.9
NPLOT
CERIG,NODE(0.9,0.2,0.02),ALL,ALL,,,,
ALLSEL
!施加载荷
/SOLU
F,NODE(-0.1,0.2,0.02),MY,-500!绕Y轴的扭矩
F,NODE(0.9,0.2,0.02),MY,500
FINISH
/SOL
ANTYPE,0
SOLVE
2.3 APDL查看结果
FINISH
/POST1
SET,FIRST
/EFACET,1
PLNSOL, S,X, 0,1.0
3. 举一反三
如果一端固定,一端施加载荷在,则得到的应力云图如下图所示