C++中cout输出字符型指针地址值的方法

转载:http://blog.csdn.net/u013467442/article/details/43666955

#include<iostream>
#include<string>
using namespace std;

int _tmain(int argc, _TCHAR* argv[])
{
    char c[3]={'a','b','c'};
    char *p=c;
    cout<<*p<<' '<<(void*)p<<endl;
    cout<<*(p+1)<<' '<<static_cast<void*>(p+1)<<endl;
    cout<<*(p+2)<<' '<<static_cast<void*>(p+2)<<endl;

    system("pause");
    return 0;
}

 

 

posted @ 2017-08-07 15:51  Henry2017  阅读(716)  评论(0编辑  收藏  举报