摘要:
char * convertToBase7(int num){ if (num==0) return "0"; char* s = (char*)calloc(1001,sizeof(char)); int pst=1000, flag=(num<0)?1 :0; num = abs(num); c 阅读全文
摘要:
int calPoints(char ** ops, int opsSize){ int arr[1000]={0}, i, pst=0, temp, sum=0; for(i=0; i<opsSize; i++){ if(isdigit(ops[i][0]) || ops[i][0] == '-' 阅读全文
摘要:
int maxProfit(int* prices, int pricesSize){ int sum=0, i, max=0; for(i=1; i<pricesSize; i++){ sum += prices[i]-prices[i-1]; if(sum<0) sum=0; if(sum>ma 阅读全文
摘要:
int maxProfit(int* prices, int pricesSize){ int ans = 0; for (int i = 1; i < pricesSize; ++i) { /* 当天价格大于前一天价格,前一天买入,当天卖出,利润累加 */ ans += fmax(0, price 阅读全文