摘要: char * countAndSay(int n){ int i,j,cnt,len; char buffer[100]={0}; char* pre = (char*)calloc(10000,sizeof(char)); sprintf(pre,"%d",1); for (i=2; i<=n; 阅读全文
posted @ 2020-10-08 16:40 温暖了寂寞 阅读(99) 评论(0) 推荐(0) 编辑