【leetcode】翻转图像

 

int** flipAndInvertImage(int** A, int ASize, int* AColSize, int* returnSize, int** returnColumnSizes){
    *returnSize=ASize;
    *returnColumnSizes=AColSize;

    for (int i=0; i<ASize; i++)
    {
        int left=0,right=*AColSize-1;
        while(left<=right){
            int temp = !A[i][left];
            A[i][left++] = !A[i][right];
            A[i][right--] = temp;
        }
    }
    return A;
}

 

posted @ 2020-09-28 10:00  温暖了寂寞  阅读(120)  评论(0编辑  收藏  举报