剑指 Offer 13. 机器人的运动范围
剑指 Offer 13. 机器人的运动范围
问题描述:
地上有一个m行n列的方格,从坐标 [0,0] 到坐标 [m-1,n-1] 。一个机器人从坐标 [0, 0] 的格子开始移动,它每次可以向左、右、上、下移动一格(不能移动到方格外),也不能进入行坐标和列坐标的数位之和大于k的格子。例如,当k为18时,机器人能够进入方格 [35, 37] ,因为3+5+3+7=18。但它不能进入方格 [35, 38],因为3+5+3+8=19。请问该机器人能够到达多少个格子?
示例 1:
输入:m = 2, n = 3, k = 1
输出:3
示例 2:输入:m = 3, n = 1, k = 0
输出:1
提示:1 <= n,m <= 100
0 <= k <= 20
//DFS
object Solution {
def movingCount(m: Int, n: Int, k: Int): Int = {
val visited = Array.fill(m+1, n+1)(false)
return dfs(visited, m, n, k, 0, 0)
}
def dfs(visited: Array[Array[Boolean]], m: Int, n: Int, k: Int, i: Int, j: Int): Int = {
if (i < 0 || i >= m || j < 0 || j >= n || visited(i)(j) == true || sum(i) + sum(j) > k) return 0
visited(i)(j) = true
return 1 + dfs(visited, m, n, k, i+1, j) + dfs(visited, m, n, k, i, j+1)
}
def sum(x: Int): Int = {
var sum = 0
var tempX = x
while (tempX > 0) {
sum += tempX % 10
tempX /= 10
}
return sum
}
}
//BFS
import scala.collection.mutable.Queue
import util.control.Breaks._
object Solution {
def movingCount(m: Int, n: Int, k: Int): Int = {
val queue = Queue[(Int, Int)]()
val visited = Array.fill(m, n)(false)
var res = 0
queue.enqueue((0, 0))
while(queue.size > 0) {
val a = queue.dequeue
val x = a._1
val y = a._2
breakable{
if (x < 0 || x >= m || y < 0 || y >= n || visited(x)(y) == true || sum(x) + sum(y) > k) break()
visited(x)(y) = true
res += 1
queue.enqueue((x+1, y))
queue.enqueue((x, y+1))
}
}
return res
}
def sum(i: Int): Int = {
var sum = 0
var tempI = i
while (tempI > 0) {
sum += tempI%10
tempI /= 10
}
return sum
}
}
//DFS
func movingCount(m int, n int, k int) int {
//visited := [m][n]bool{}
visited := make([][]bool, m)
for i := 0; i < m; i++ {
visited[i] = make([]bool, n)
}
return dfs(visited, m, n, k, 0, 0)
}
func dfs(visited [][]bool, m, n, k, i, j int) int {
if i < 0 || i >= m || j < 0 || j >= n || visited[i][j] == true || sum(i) + sum(j) > k { return 0}
visited[i][j] = true
return 1 + dfs(visited, m, n, k, i+1, j) + dfs(visited, m, n, k, i, j+1)
}
func sum(x int) int {
res := 0
for (x > 0) {
res += x % 10
x /= 10
}
return res
}
//BFS
import "container/list"
func movingCount(m int, n int, k int) int {
res := 0
visited := make([][]bool, m)
for i := 0; i < m; i++ {
visited[i] = make([]bool, n)
}
queue := list.New()
queue.PushBack(0)
queue.PushBack(0)
for (queue.Len() > 0) {
temp := queue.Front()
x := temp.Value.(int)
queue.Remove(temp)
temp = queue.Front()
y := temp.Value.(int)
queue.Remove(temp)
if x < 0 || x >= m || y < 0 || y >= n || visited[x][y] == true ||sum(x) + sum(y) > k {continue}
visited[x][y] = true
res += 1
queue.PushBack(x+1)
queue.PushBack(y)
queue.PushBack(x)
queue.PushBack(y+1)
}
return res
}
func sum(x int) int {
res := 0
for (x > 0) {
res += x%10
x /= 10
}
return res
}