C# 实现 Nginx 平滑加权轮询算法

代码很简单,算法很经典!

 

1. 定义实体类

    public struct ServerConfig
    {
        //初始权重
        public int Weight {get;set;}

        //当前权重
        public int Current {get;set;}

        //服务名称
        public string Name {get;set;}
    }

2. 算法

    // 找出数组中当前权重最小的那个服务的index,并把那个服务的当前权重减去总权重。
public static int NextServerIndex(ServerConfig[] serverConfigArray) { int index = -1; int totalWeight = 0; int size = serverConfigArray.Count(); for(int i = 0; i< size; i++) { serverConfigArray[i].Current += serverConfigArray[i].Weight; totalWeight += serverConfigArray[i].Weight; if (index == -1 || serverConfigArray[index].Current < serverConfigArray[i].Current) { index = i; } } serverConfigArray[index].Current -= totalWeight; return index; }

3.调用

 

    public static void TestServerAssignment()
    {
        //构建三台服务器
        var servers = new ServerConfig[] {
            new ServerConfig{Name="A", Weight = 4},
            new ServerConfig{Name="B", Weight = 2},
            new ServerConfig{Name="C", Weight = 1}
        };
        int beUsedIndex = 0;
        int sum = servers.Sum(m => m.Weight); //总权重
        //模拟调用服务次数为总权重数
        for(int i=0; i<sum; i++)
        {
            beUsedIndex = NextServerIndex(servers);
            Console.WriteLine("Current Server is {0}, its weight is {1}", 
                    servers[beUsedIndex].Name, servers[beUsedIndex].Weight);
        }
    }

4.运行结果

 

 

 

 

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*** No matter how far you go, looking back is also necessary. ***
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posted @ 2018-07-24 09:10  Gangle  阅读(496)  评论(0编辑  收藏  举报