// language c
// 剑指56-I
// https://leetcode-cn.com/problems/shu-zu-zhong-shu-zi-chu-xian-de-ci-shu-lcof/
// 通过了,但是肯定能优化,需要用到亦或,不太懂
/**
* Note: The returned array must be malloced, assume caller calls free().
*/
// 排序是nlogn不太符合,但是好先试试吧
int* singleNumbers(int* nums, int numsSize, int* returnSize){
returnSize[0] = 2;
int partition(int arr[],int low, int high){
int pivot = arr[low];
while (low <high){
while(low <high && arr[high] >=pivot) high--;
arr[low] = arr[high];
while(low <high && arr[low] <= pivot) low++;
arr[high] = arr[low];
}
arr[low] = pivot;
return low;
}
void quick_sort_inside(int arr[], int start, int end){
int pivot = partition(arr,start,end);
if (start < pivot-1) quick_sort_inside(arr, start, pivot-1);
if (end > pivot+1) quick_sort_inside(arr, pivot+1, end);
}
quick_sort_inside(nums,0,numsSize-1);
int a;
int b;
bool a_found =false,done = false;
void fill(int m){
if(a_found){
b = m;
done = true;
}else{
a = m;
a_found = true;
}
if(nums[0]<nums[1])
fill(nums[0]);
if(nums[numsSize-1]>nums[numsSize-2]){
fill(nums[numsSize-1])
if(done){
nums[0] = a;
nums[1] = b;
return nums;
}
}
for(int i=1; i<numsSize-1;i++){
if((nums[i]>nums[i-1])&&(nums[i]<nums[i+1])){
fill(nums[i])
if(done){
nums[0] = a;
nums[1] = b;
return nums;
}
}
}
return nums;
}
// language c
// 剑指56-II
// https://leetcode-cn.com/problems/shu-zu-zhong-shu-zi-chu-xian-de-ci-shu-ii-lcof/
// 把I的代码改了改,大差不差
/**
* Note: The returned array must be malloced, assume caller calls free().
*/
// 排序是nlogn不太符合,但是好先试试吧
int singleNumber(int* nums, int numsSize){
int partition(int arr[],int low, int high){
int pivot = arr[low];
while (low <high){
while(low <high && arr[high] >=pivot) high--;
arr[low] = arr[high];
while(low <high && arr[low] <= pivot) low++;
arr[high] = arr[low];
}
arr[low] = pivot;
return low;
}
void quick_sort_inside(int arr[], int start, int end){
int pivot = partition(arr,start,end);
if (start < pivot-1) quick_sort_inside(arr, start, pivot-1);
if (end > pivot+1) quick_sort_inside(arr, pivot+1, end);
}
quick_sort_inside(nums,0,numsSize-1);
if(nums[0]<nums[1]){
return nums[0];
}
if(nums[numsSize-1]>nums[numsSize-2]){
return nums[numsSize-1];
}
for(int i=1; i<numsSize-1;i++){
if((nums[i]>nums[i-1])&&(nums[i]<nums[i+1])){
return nums[i];
}
}
return 0;
}