c语言实现的栈---链表+数组
1.数组实现的栈
#include <stdio.h> #include <string.h> #include <stdlib.h> #define MAXSIZE 5 /** *数组实现的栈,缺点,容量固定 **/ typedef struct{ int data[MAXSIZE]; int index; }Stack; Stack s; /** *入栈,成功返回1,否则0 **/ int push(int e){ int rt = 0; if(s.index < MAXSIZE-1){ s.data[++s.index] = e; }else{ rt = -1; } return rt; } /** *初始化栈 */ int clear(void){ s.index = -1; return 0; } /** *判断栈是否为空 **/ int isempty(void){ return (s.index == -1)?1:0; } /** *出栈,弹出栈顶元素 **/ int pop(void){ int t=0; if(s.index != -1){ t=s.data[s.index--]; } return t; } /** *栈内元素打印 */ int displaystack(void){ int p=s.index; while(s.index!=-1){ printf("currentdata:%d\n",s.data[s.index--]); } s.index = p; return 0; } int main(void){ clear(); puts("after push:"); push(1); push(2); push(3); push(4); push(5); push(6); printf("s.index=%d:\n",s.index); displaystack(); puts("\nafter pop"); pop(); displaystack(); return 0; }
2.链表实现
#include <stdio.h> #include <string.h> #include <stdlib.h> /** *链表实现的栈 **/ typedef struct linklist{ int data; struct linklist *next; struct linklist *pre; }Link; typedef struct{ int index;//栈顶 int empty;//链表是否为空标志 Link *head; }StackLink; StackLink s; /** *入栈 **/ int push(int e){ Link *element,*end; if(s.index==0){ end = (Link *)malloc(sizeof(Link)); s.empty = -1; }else{ end = s.head; } element = (Link *)malloc(sizeof(Link)); element->data = e; element->pre = end; element->next = NULL; end->next = element; end = element; s.index ++; s.head = end; return 0; } /** *标志位设为空 **/ int clear(){ s.empty = 0; return 0; } /** *判断栈是否为空 **/ int isempty(void){ return (s.empty==0)?1:0; } /** *出栈,弹出栈顶元素 **/ int pop(void){ int t=0; if(s.index != 0&&s.empty == -1){ s.index --; Link *temp,*p; t=s.head->data; temp=s.head; p = temp->pre; free(s.head); s.head = p; }else{ s.empty = 0; } return t; } /** *栈内元素打印 */ int displaystack(void){ Link *t = s.head; while(s.head->pre!=NULL){ printf("currentdata:%d\n",s.head->data); s.head=s.head->pre; } s.head = t; return 0; } int main(void){ clear(); puts("after push:"); for(int i=0;i<100;i++) push(i); printf("s.index=%d:\n",s.index); displaystack(); puts("\nafter pop"); pop(); pop(); displaystack(); return 0; }