hdu-1166 敌兵布阵---树状数组模板
题目链接:
http://acm.hdu.edu.cn/showproblem.php?pid=1166
题目大意:
维护动态的区间和,单点更新,就是模板题
1 #include<iostream> 2 #include<algorithm> 3 #include<set> 4 #include<cstring> 5 #include<cstdio> 6 using namespace std; 7 const int maxn = 100000 + 10; 8 typedef long long ll; 9 int tree[maxn]; 10 int n; 11 int lowbit(int x) 12 { 13 return x & (-x); 14 } 15 void add(int x, int d) 16 { 17 while(x <= n) 18 { 19 tree[x] += d; 20 x += lowbit(x); 21 } 22 } 23 ll sum(int x) 24 { 25 ll ret = 0; 26 while(x > 0)//此处等于0会导致无限循环 27 { 28 ret += tree[x]; 29 x -= lowbit(x); 30 } 31 return ret; 32 } 33 int main() 34 { 35 int T, cases = 0; 36 scanf("%d", &T); 37 while(T--) 38 { 39 scanf("%d", &n); 40 memset(tree, 0, sizeof(tree)); 41 int x, y; 42 for(int i = 1; i <= n; i++) 43 { 44 scanf("%d", &x); 45 add(i, x); 46 } 47 char s[8]; 48 printf("Case %d:\n", ++cases); 49 while(scanf("%s", s) && s[0] != 'E') 50 { 51 scanf("%d%d", &x, &y); 52 if(s[0] == 'A') 53 { 54 add(x, y); 55 } 56 else if(s[0] == 'S') 57 { 58 add(x, -y); 59 } 60 else if(s[0] == 'Q') 61 { 62 ll ans = sum(y) - sum(x - 1); 63 printf("%lld\n", ans); 64 } 65 } 66 } 67 }
越努力,越幸运