如何一键导出k8s某个namespace下的所有yaml？

脚本如下

#!/bin/bash
set -e

useage(){
    echo "useage:"
    echo "  dumpk8s.sh DUMPDIR [NAMESPACE]"
}

if [ $# -lt 1 ];then
    useage
    exit
fi

DUMPDIR=$1
NAMESPACE=$2

list_names(){
    kubectl -n "${1}" get "${2}" -o custom-columns='NAME:metadata.name' --no-headers
}

dump_workload(){
    local NAMESPACE=$1
    local WORKLOAD_NAME=$2
    local i
    mkdir -p "${DUMPDIR}/${NAMESPACE}/${WORKLOAD_NAME}"
    mapfile -t WORKLOADS < <(list_names "${NAMESPACE}" "${WORKLOAD_NAME}")
    for ((i=1;i<=${#WORKLOADS[@]};i++ )); do
        WORKLOAD="${WORKLOADS[$i-1]}"
        echo "Dumping ${NAMESPACE} ${WORKLOAD_NAME} ${WORKLOAD}"
        kubectl -n "${NAMESPACE}" get "${WORKLOAD_NAME}" "${WORKLOAD}" -o yaml --export > "${DUMPDIR}/${NAMESPACE}/${WORKLOAD_NAME}/${WORKLOAD}.yaml" 2>/dev/null
    done
}

if [ -z "${NAMESPACE}" ];then
mapfile -t WORKLOAD_NAMES < <(kubectl api-resources -oname --namespaced=false | grep -vE "(componentstatuses|authentication.k8s.io|authorization.k8s.io)")
NAMESPACE="default"
else
mapfile -t WORKLOAD_NAMES < <(kubectl api-resources -oname --namespaced=true | grep -vE "(bindings|secrets|authorization.k8s.io)")
fi
mkdir -p "${DUMPDIR}/${NAMESPACE}"
for ((i=1;i<=${#WORKLOAD_NAMES[@]};i++ )); do
    WORKLOAD_NAME="${WORKLOAD_NAMES[$i-1]}"
    dump_workload "${NAMESPACE}" "${WORKLOAD_NAME}"
done

echo "Done"

使用方法

dumpk8s ./testnamespace testnamespace