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转载http://duqiangatom.blog.163.com/blog/static/11502518201051083013421/

1、rank() over()、dense_rank() over()、row_number() over()

--排名有重复时,跳过一个,如若有2个第二名,则直接到4,无排名为3的 

 SELECT site_id, SUM(sale_lottery_cnt),rank() over(ORDER BY SUM(sale_lottery_cnt) DESC)
  FROM test

 WHERE report_date = trunc(SYSDATE - 14)
 GROUP BY site_id;

--排名有重复时,如若有2个第二名,下一个还是排名为3,不跳跃,排名连续
SELECT site_id, SUM(sale_lottery_cnt),dense_rank() over(ORDER BY SUM(sale_lottery_cnt) DESC)

  FROM test
 WHERE report_date = trunc(SYSDATE - 14)
 GROUP BY site_id;
 
 --排名不可能有重复,即使相同,也会是不同的名次
 SELECT site_id, SUM(sale_lottery_cnt),Row_number() over(ORDER BY SUM(sale_lottery_cnt) DESC)

  FROM test WHERE report_date = trunc(SYSDATE - 14)
 GROUP BY site_id;

 应用1:删除重复记录

 CREATE TABLE test1 AS
         SELECT tt.object_id, tt.object_name FROM user_objects;

 INSERT INTO test1
  SELECT tt.object_id, tt.object_name FROM user_objects tt; --n条记录
 SELECT COUNT(*) FROM user_objects; --2n条
 DELETE FROM test1
 WHERE ROWID IN(SELECT row_id FROM (SELECT ROWID AS row_id,
                        row_number() over(PARTITION BY tt.object_id, tt.object_name ORDER BY ROWID) AS rnn
                   FROM test1 tt) rn  WHERE rn.rnn <>1);--剩下n条记录

更快的一种方法,用关联delete

delete  from  test1 t where  t.rowid> (select min(rowid) from test1 d where t.rowid=d.rowid); 

2、lag(.column, offset) +lead(column ,offset)  over(partition by c1 order by c2) offset default is 1

ddl test

create table TEST2
(
  SITE_ID          NUMBER not null,
  SALE_LOTTERY_CNT NUMBER
);

 insert into test2 (SITE_ID, SALE_LOTTERY_CNT)
values (132623, 10);

insert into test2 (SITE_ID, SALE_LOTTERY_CNT)
values (633423, 4);

insert into test2 (SITE_ID, SALE_LOTTERY_CNT)
values (132523, 2);

insert into test2 (SITE_ID, SALE_LOTTERY_CNT)
values (183523, 2);

insert into test2 (SITE_ID, SALE_LOTTERY_CNT)
values (183524, 4);

insert into test2 (SITE_ID, SALE_LOTTERY_CNT)
values (183524, 19);

insert into test2 (SITE_ID, SALE_LOTTERY_CNT)
values (183623, 4);

insert into test2 (SITE_ID, SALE_LOTTERY_CNT)
values (132623, 19);

SELECT site_id, sale_lottery_cnt,
       lag(sale_lottery_cnt, 1) over(PARTITION BY site_id ORDER BY sale_lottery_cnt DESC NULLS FIRST) AS "分组排序后取前一个记录字段值",
       lead(sale_lottery_cnt, 1) over(PARTITION BY site_id ORDER BY sale_lottery_cnt DESC NULLS FIRST) AS "分组排序后取后一个记录字段值"
  FROM test
 WHERE report_date = trunc(SYSDATE - 14);

3、min(c1)/max/avg/sum over(partition by c2) 返回分组中的聚合值,但是行数不变,不像聚合函数行数变少

SELECT site_id, sale_lottery_cnt, MAX(sale_lottery_cnt) over(PARTITION BY site_id),
       MIN(sale_lottery_cnt) over(PARTITION BY site_id),
       AVG(sale_lottery_cnt) over(PARTITION BY site_id),
       SUM(sale_lottery_cnt) over(PARTITION BY site_id)
  FROM test2
 ORDER BY 1;--行数无变化,前后行数相等

SELECT site_id, MAX(sale_lottery_cnt), SUM(sale_lottery_cnt), AVG(sale_lottery_cnt),
       MIN(sale_lottery_cnt)
  FROM test2
 GROUP BY site_id;--返回聚合完的行数,与分组数相同

4、aggregate function(列) keep (dense_rank  first  [last] order by c2 desc)   over(partition by c1 ) )

  SELECT site_id, sale_lottery_cnt,
        --先按分组排序,然后取第一个或者最后一个,但是也有可能第一个或者最后一个有多于1条记录,此时,前面的max聚合函数就起作用了
       MAX(sale_lottery_cnt) keep(dense_rank LAST ORDER (BY sale_lottery_cnt DESC) over(PARTITION BY site_id),
       MIN(sale_lottery_cnt) keep(dense_rank LAST ORDER BY sale_lottery_cnt DESC) over(PARTITION BY site_id)
  FROM test2;

5、RATIO_TO_REPORT (column) over()计算 column/sum(column)

        SELECT ID,SORT,color,ratio_to_report(NUM) OVER()  FROM TEST;

 1 book       red        0.2
1 book       blue       0.133333333333333
1 book       green      0.133333333333333
1 book       red        0.133333333333333
1 car        blue       0.133333333333333
1 car        red        0.133333333333333
2 car        red        0.133333333333333

posted on 2013-01-30 16:11  future2012lg  阅读(243)  评论(0编辑  收藏  举报